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Darina [25.2K]
3 years ago
8

Evaluate the expression

Mathematics
2 answers:
GuDViN [60]3 years ago
6 0

I think the answer is 0.83, tell me is it correct ok, I try to help you

malfutka [58]3 years ago
5 0

Answer:

7/12 or 0.583333333333...

Step-by-step explanation:

calculator

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serious [3.7K]
-2 3/5 would be the answer to the problem
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S(n) is a function that square numbers it can be written in equation from as S (n) = N squart 2 what is the value of S(11)
Pani-rosa [81]
f(n)=n^2 is what I think you mean
f(11)=11^2=121
7 0
4 years ago
If the work required to stretch a spring 2 ft beyond its natural length is 6 ft-lb, how much work is needed to stretch it 6 in.
mel-nik [20]

Answer:

0.375 feet-lb

Step-by-step explanation:

We have been given that the work required to stretch a spring 2 ft beyond its natural length is 6 ft-lb. We are asked to find the work needed to stretch the spring 6 in. beyond its natural length.

We can represent our given information as:

6=\int\limits^2_0 {F(x)} \, dx

We will use Hooke's Law to solve our given problem.

F(x)=kx

Substituting this value in our integral, we will get:

6=\int\limits^2_0 {kx} \, dx

Using power rule, we will get:

6=\left[ \frac{kx^2}{2} \right ]^2_0

6=\frac{k(2)^2}{2}-\frac{k(0)^2}{2}

6=\frac{4k}{2}-0\\\\k=3

We know that 6 inches is equal to 0.5 feet.

Work needed to stretch it beyond 6 inches beyond its natural length would be \int\limits^{0.5}_0 {kx} \, dx =\int\limits^{0.5}_0 {3x} \, dx

Using power rule, we will get:

\int\limits^{0.5}_0 {3x} \, dx = \left [\frac{3x^2}{2}\right]^{0.5}_0

\frac{3(0.5)^2}{2}-\frac{3(0)^2}{2}\Rightarrow \frac{3(0.25)}{2}-0=\frac{0.75}{2}=0.375

Therefore, 0.375 feet-lb work is needed to stretch it 6 in. beyond its natural length.

3 0
3 years ago
What is the nearest whole number f or 8 1/8
mina [271]
8 1/8 rounded to the nearest whole number is 8. Hope this helps you out!
3 0
3 years ago
−2√24+2√2−2√8 simplify
Kamila [148]

Answer:

Step-by-step explanation:

-2\sqrt{24}+2\sqrt{2}-2\sqrt{8}=-2\sqrt{2*2*2*3}+2\sqrt{2}-2\sqrt{2*2*2}\\\\=-2*2\sqrt{2*3}+2\sqrt{2}-2*2\sqrt{2}\\\\=-4\sqrt{6}+2\sqrt{2}-4\sqrt{2}\\\\=-4\sqrt{6}+(2-4)\sqrt{2}\\\\=-4\sqrt{6}-2\sqrt{2}

3 0
3 years ago
Read 2 more answers
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