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3 years ago

Last trigonometry question plz help me for 30 points

Mathematics

1 answer:

REY [17]3 years ago

7 0

Answer:

Step-by-step explanation:

Segment WX = 23 by the 30 60 90 triangle theorem which states that the longer leg is sqrt3 times the length of the shorter leg.

Segment XY = 26 by the 30 60 90 triangle theorem that states the hypotenuse is twice the length of the shorter leg

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The difference between two numbers is 5. six times the larger number is 8 times the smaller number. write a system of equations

Ksenya-84 [330]

X - y = 5....x = 5 + y
6x = 8y

6(5 + y) = 8y
30 + 6y = 8y
30 = 8y - 6y
30 = 2y
15 = y

x - y = 5
x - 15 = 5
x = 15 + 5
x = 20

ur 2 numbers are : 20 and 15

6 0

2 years ago

Find the perimeter and area of each finger below

luda_lava [24]

Can you send a picture?

8 0

2 years ago

Queston 132

Sever21 [200]

Answer:

68cm^2

Step-by-step explanation:

<h2>A trapezium is a type of quadrilateral with the two opposite sides parallel.</h2>

Area of a trapezium= 1/2(sum of parallel sides)×height

Area of the trapezium= 1/2(5+3)×17

Area of the trapezium= 1/2(8)×17

Area of the trapezium=4×17= 68cm^2

4 0

2 years ago

Differentiate the following functions (x^3+1)(x-2)÷x^2

Masja [62]

Given:

The given function is:

$\dfrac{(x^3+1)(x-2)}{x^2}$

To find:

The differentiation of the given function.

Solution:

Consider the given function,

$y=\dfrac{(x^3+1)(x-2)}{x^2}$

It can be written as:

$y=\dfrac{(x^3)(x)+(x^3)(-2)+(1)(x)+(1)(-2)}{x^2}$

$y=\dfrac{x^4-2x^3+x-2}{x^2}$

$y=\dfrac{x^4}{x^2}-\dfrac{2x^3}{x^2}+\dfrac{x}{x^2}-\dfrac{2}{x^2}$

$y=x^2-2x+\dfrac{1}{x}-\dfrac{2}{x^2}$

Differentiate with respect to x.

$y'=\dfrac{d}{dx}(x^2)-\dfrac{d}{dx}(2x)+\dfrac{d}{dx}(x^{-1})-\dfrac{d}{dx}\2(x^{-2})$

$y'=2x-2(1)+(-x^{-2})-2(-2x^{-3})$

$y'=2x-2-\dfrac{1}{x^2}+\dfrac{4}{x^3}$

Therefore, the differentiation of the given function is $2x-2-\dfrac{1}{x^2}+\dfrac{4}{x^3}$ .

8 0

3 years ago

The length and width of a rectangle are measured as 31 cm and 28 cm, respectively, with an error in measurement of at most 0.1 c

MissTica

Answer:

$\Delta A = 5.9\,cm^{2}$

Step-by-step explanation:

The area of an rectangle is given by the following formula:

$A = w\cdot h$

Where:

$w$ - Width, in centimeters.

$h$ - Height, in centimeters.

The differential of the expression is derived hereafter:

$\Delta A = \frac{\partial A}{\partial w} \cdot \Delta w + \frac{\partial A}{\partial h}\cdot \Delta h$

$\Delta A = h \cdot \Delta w + w \cdot \Delta h$

$\Delta A = (31\,cm)\cdot (0.1\,cm) + (28\,cm)\cdot (0.1\,cm)$

$\Delta A = 5.9\,cm^{2}$

5 0

3 years ago