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2 years ago

Can someone help me find the value of z? ⅔z + 1 = 13

Mathematics

1 answer:

sergey [27]2 years ago

4 0

Answer:

z = 18

Step-by-step explanation:

Given: ⅔z + 1 = 13

Subtract one from both sides: ⅔z = 12

Multiply both sides by the inverse of 2/3, which is 3/2: z = 18

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you can speed from 0 to 25 m/s in 25 seconds and your friend can speed up from 0 to 6 m/s in 6 seconds. who is faster

aksik [14]

Answer:

Neither; see below

Step-by-step explanation:

Your acceleration: $a=\frac{\Delta v}{\Delta t}=\frac{25-0}{25}=1m/s^2$

Your friend's acceleration: $a=\frac{\Delta v}{\Delta t}=\frac{6-0}{6}=1m/s^2$

Therefore, since both you and your friend accelerate at the same rate, neither is faster.

7 0

2 years ago

Help me with this please

nalin [4]

This is incorrect. X can be negative, making the expression on the left less than 0. If x were -10, then:
3 x -10 + 1 > 0
-30 + 1 > 0
-29 > 0
Is NOT true.

5 0

3 years ago

The width of a rectangle is the length minus 4 units. The area of the rectangle is 12 units. What is the width in units of the r

Genrish500 [490]

Answer:

width = 2 units

Step-by-step explanation:

If the length of a rectangle is (x) units, then that means that the width of a rectangle is x - 4 units.

the area of a rectangle is length * width

so just substitute the values that we have now.

x (length) * (x-4) width = 12 (area of rectangle)

so that gives us

x^2 - 4x =12

subtract 12 from both sides

x^2 - 4x - 12 =0

now factor this equation

x^2 + 2x - 6x -12 = 0

x(x+2) - 6(x+2) = 0

(x-6)(x+2) = 0

x = 6, or x = -2 REMEMBER THAT VALUE OF x = LENGTH, IT CANNOT BE NEGATIVE AS YOU CANT HAVE NEGATIVE VALUE OF A SIDE

length = 6, and width = 6 -4 = 2

8 0

3 years ago

Read 2 more answers

What’s the answer (anyone ?)

alexgriva [62]

Answer: Idek if that's a question

Step-by-step explanation:

6 0

2 years ago

QRINC offered new employees a starting salary of $34,862 in 2013. What would a comparable starting salary have been in 2003?

Vlad1618 [11]

Complete Question

Table of Annual CPI values

2003-184.00

2004-188.90

2005-195.3

2006-201.6

2007-207.342

2008-215.303

2009-214.537

2010-218.056

2011-224.939

2012-229.594

2013-232.957

2014-236.736

QRINC offered new employees a starting salary of $34,862 in 2013. What would a comparable starting salary have been in 2003?

Answer:

$C=27535.5881128$

Step-by-step explanation:

From the question we are told that

CPI for 2003(index)=2003-184.00

CPI for 2013(index)=2013-232.957

Starting salary in 2013 at $34,862

Generally comparable starting salary C is given as

$C=\frac{starting salary}{CPI for 2013(index} *CPI for 2003(index)$

$C=\frac{34,862}{232.957} *184$

Therefore C the comparable starting salary is givrn to be

$C=27535.5881128$

$C=27536 appro$

8 0

3 years ago