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sergey [27]
2 years ago
9

Please help will give 10 points!!!

Mathematics
1 answer:
AlexFokin [52]2 years ago
4 0

Answer:

m = variables

+4 = Coefficients

-7 = Coefficients

and 2 and 6 are Constants

Hope this helps!

Step-by-step explanation:

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UREGENT !! Determine the slope of the given equation: (give the slope as a decimal.)
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Answer:

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Step-by-step explanation:

4 0
3 years ago
Help on this please!
Nana76 [90]
2/9 - 7/12

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8 0
3 years ago
If the mean weight of 4 backfield members on the football team is 221 lb and the mean weight of the 7 other players is 202 lb, w
MatroZZZ [7]

Let x_1, x_2, x_3, x_4, x_5, x_6, x_7, x_8, x_9, x_{10}, x_{11} be the weight of i-th player.

1. If the mean weight of 4 backfield members on the football team is 221 lb, then

\dfrac{x_1+x_2+x_3+x_4}{4}=221\ lb.

2. If the mean weight of the 7 other players is 202 lb, then

\dfrac{x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}}{7}=202\ lb.

3. From the previous statements you have that

x_1+x_2+x_3+x_4=221\cdot 4=884 \lb,\\ \\x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}=202\cdot 7=1414\ lb.

Add these two equalities and then divide by 11:

x_1+x_2+x_3+x_4+x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}=884+1414=2298\ lb,\\ \\\dfrac{x_1+x_2+x_3+x_4+x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}}{11}=\dfrac{2298}{11}=208\dfrac{10}{11}\ lb.

Answer: the mean weight of the 11-person team is 208\dfrac{10}{11}\ lb.

4 0
3 years ago
Haruka hiked several kilometers in the morning. She only hiked 6 kilometers in the afternoon, which was 25% less she had hiked i
SOVA2 [1]

WEW can use a simple equation to solve this

Let x be the number of kilometers she hiked in the morning . Then

x - 0.25x = 6 (Note 0.25 = 25 %)

0.75x = 6

x = 6 / 0.75 = 8 kilometers answer

4 0
4 years ago
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