Answer : rotation of 90 counterclockwise° about the origin and then translation 2 unit up.
Explanation : In Δ RST, it is an right triangle with ∠R being the right angle. When we draw this triangle we see that long side of the Δ is close to the origin and the short one is below ∠R.
Now, Δ R'S'T', is also a right triangle. But he long side is parallel to the y axis and ∠S' is now above ∠R' instead of ∠S being to right of ∠R in the original Δ.
which clearly shows that the Δ is rotated at 90 degrees counter clockwise.
On drawing a new Δ; The point R" is at (1,-4), S" at (1,-1), and T" at (2,-4).
All three of these points are 2 units below the points R' S' T'.
We need to translate the triangle 2 units higher.
Therefore, the answer is to perform rotation of 90 counterclockwise° about the origin and then translation 2 unit up.
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y = -5/6x + 3
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Connie bike faster than joey
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20
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I don't know I just Lucky guessed but hope it helps and I was right
3xy over 8 is the answer go to mathway
and you can find your answer and it shows you how to do it
