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Sedaia [141]
3 years ago
11

If point B is located at (0, 2) and is translated to point B' with coordinates (1,-1), which translation did point B undergo?​

Mathematics
1 answer:
wolverine [178]3 years ago
4 0
The correct answer is A
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seropon [69]
I hope this helps you

4 0
3 years ago
Twice as many students are in the chess club as in the fencing club.The number of students in the fencing club is one fifth the
jekas [21]

Answer:

28 students

Step-by-step explanation:

Let number of students in cooking club = x

Number of students in fencing club = 1/5 x

Number of students in chess club = 2(1/5)x

Since, There are 42 more students in the cooking club than in the chess club

Then ;

Number of students in chess club = Number of students in cooking club - 42

2(1/5)x = x - 42

(2/5)x - x = - 42

(2/5)x - x = - 42

-0.6x = - 42

x = 42 / 0.6

x = 70

Hence, number of students in chess club :

(2/5) * 70 = 28

4 0
3 years ago
Write as<br> logarithm with base 4:<br> 4<br> -5<br> 2<br> -4
NeX [460]

Answer:

log_4(256)=4

log_4(1/1024)=-5

log_4(16)=2

log_4(1/256)=-4

Step-by-step explanation:

We want to write a number, x, such that

Log_4(y)=x.

In exponential form that is 4^x=y.

So first number is x=4.

4^4=256 which means log_4(256) is 4 as a logarithm with base 4.

The second number is x=-5.

4^-5=1/4^5=1/1024 which means log_4(1/1024) is -5 as a logarithm with base 4.

The third number is x=2.

4^2=16 so log_4(16) is 2 as a logarithm with base 4.

The fourth number is x=-4.

Since 4^4=256 then 4^-4=1/256 which means -4 as a logarithm with base 4 is log_4(1/256).

8 0
3 years ago
If the unit price of oranges is 0.08 per pound and Jim pays 2.08 how many oranges does he buy
kobusy [5.1K]
26 I believe, I'm pretty sure :)
3 0
3 years ago
What is the positive solution to the equation 0 = –x2 + 2x + 1? Quadratic formula: x = StartFraction negative b plus or minus St
katrin [286]

Answer:

x = 2 + √2

x = 2 - √2

Step-by-step explanation:

- x² + 2x + 1 = 0

x² - 2x - 1 = 0

Here,

a = <em>1</em>

b = <em>- 2</em>

c = <em>- 1</em>

Now,

Discriminant

D = b² - 4ac

= (-2)² - 4(1)(-1)

= 4 + 4

= 8

=2√2 > 0

<em><u>Real and </u></em><em><u>D</u></em><em><u>istinct roots </u></em>

x = - b +- √b² - 4ac/2a

= - (-2) +- √ = (-2)² - 4(1)(-1)/2(1)

= 2 +- √4 + 4/2

= 2 +- √8/2

= 2 +- 2√2/2

= 2 +- √2

x = 2 + √2 or x = 2 - √2

7 0
3 years ago
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