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ASHA 777 [7]
2 years ago
13

Rewrite 1/5 barrel 1/2 hour as a unit rate

Mathematics
2 answers:
zmey [24]2 years ago
5 0

Answer:

B!!

Step-by-step explanation:

Step2247 [10]2 years ago
4 0

<u><em>Answer:</em></u>

<u><em>Option B or 2/5 barrels per hour</em></u>

<u><em>Step-by-step explanation:</em></u>

<u><em>1/5 = 0.2</em></u>

<u><em>1/2 = 0.5</em></u>

<u><em>=> 0.2/0.5</em></u>

<u><em>=> 2/5</em></u>

<u><em>Option B is correct</em></u>

<u><em>Please give me brainliest :)</em></u>

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How do I find X thanks​
Ivan

Answer:

x = 60

Step-by-step explanation:

By applying mean ratio theorem in the given right triangles ΔABC and ΔBDC,

\frac{AD}{BD}=\frac{BD}{DC}

BD² = AD × DC

BD² = 36 × 64

BD = \sqrt{36\times 64}

BD = 48

By applying Pythagoras theorem in right triangle ΔADB,

AB² = AD² + BD²

x² = (48)² + (36)²

x² = 3600

x = 60

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3 years ago
What's the vertex form of the function?
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3 years ago
How do I set up the equation for this word problem? A takes 1/2 of the diamonds plus 1 from the table. B takes 2/3 of what remai
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The first thief takes (1/2 x + 1) .  What remains ?   x - (1/2x + 1)

So the 2nd thief takes  2/3 of  [  x - (1/2x + 1) ]

   What remains ?    x - 2/3 [ x - (1/2x + 1) ]

So the 3rd thief takes    2/3 of  { x - 2/3 [ x - (1/2x + 1) ] }  and he takes 1 more .

   What remains ?    x - ( 2/3 { x - 2/3 [ x - (1/2x + 1) ] } + 1 )

And that whole ugly thing is equal to ' 1 ', so you can solve it for 'x'..

The whole problem from here on is an exercise in simplifying
an expression with a bunch of 'nested' parentheses in it.  
===============================================
This is a lot harder than just solving the problem with logic and
waving your hands in the air.  Here's how you would do that:

Start from the end and work backwards:

-- One diamond is left.
-- Before the 3rd thief took 1 more, there were 2.
-- That was 1/3 of what was there before the 3rd man took 2/3.
So he found 6 when he arrived.
-- 6 was 1/3 of what was there before the second thief helped himself.
So there were 18 when the 2nd man arrived.
-- 18 was 1 less than what was there before the first thief took 1 extra.
So he took his 1 extra from 19.
-- 19 was the remaining after the first man took 1/2 of all on the table.
So there were 38 on the table when he arrived.

Thank you for your generous 5 points.


 
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