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aleksandr82 [10.1K]
2 years ago
7

What are the four main Chambers of the heart.Can you pls explain them?​

Biology
2 answers:
forsale [732]2 years ago
7 0

<u>The heart has four chambers: two atria and two ventricles. The right atrium receives oxygen-poor blood from the body and pumps it to the right ventricle. The right ventricle pumps the oxygen-poor blood to the lungs. The left atrium receives oxygen-rich blood from the lungs and pumps it to the left ventricle.</u>

OLEGan [10]2 years ago
3 0

Answer:

The heart has four chambers: two atria and two ventricles. The right atrium receives oxygen-poor blood from the body and pumps it to the right ventricle. The right ventricle pumps the oxygen-poor blood to the lungs. The left atrium receives oxygen-rich blood from the lungs and pumps it to the left ventricle.

Explanation:

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Given that polyurethane is a huge polymer (mw &gt;&gt;?????????,????????? daltons), why is it important that the polyurethanase
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Polyurethanase is an enzyme emitted by the microorganism so as to break polyurethane. Since the polymer is a significant wellspring of energy for the life form, it should be separated all together for etpum"s development.

Further details

Polyurethane

It is a polymer made out of organic units and carbamate links join them. While most polyurethanes are thermosetting polymers that don't liquefy when warmed, thermoplastic polyurethanes are likewise accessible. Polyurethanes are available in numerous parts of present-day life. They present a class of polymers that have discovered a far-reaching use in the medical and mechanical fields. Polyurethanes can be found in items such as furniture, coatings, cement, constructional materials, paints, elastomers, filaments and paddings. Polyurethane ought to be curtailed to PUR in consistence with authority German and International benchmarks.

Polyurethanase

It can be defined as such an enzyme which is secreted by microbes and used for the breakdown of polyurethane. In this breakdown process energy is released that is utilized by microorganisms.

Bio-degradation of Polyurethane

In spite of their microbial obstruction, polyurethane is attacked by microscopic organisms however the component to explain its bio-degradation is unknown. There are reports from microscopic organisms and parasites that are equipped for the breakdown of polyurethane yet the examinations about the proteins that assault the plastic are centered around bacterial compounds as it were. The enzyme is of sort esterase and protease for the most part since these chemicals are unspecific and can perceive a few regions in the polyurethane particle and hydrolyze it.

Answer details

Subject: Biology

Level: College

Keywords

  • Polyurethane
  • Polyurethanase
  • Bio-degradation of Polyurethane

Learn more to evaluate

brainly.com/question/10560288

brainly.com/question/12603071

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How does therapy help in the treatment of depression
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Having someone to talk with about your thoughts and issues can help you feel better. Emotional support from someone who cares also helps. This is usually what therapy is for...
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3 years ago
What rocks will likely weather the least
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Answer:

Rocks are in dry climate

Explanation:

Several types of rock , like granite, are very repellent to weathering. Moreover, igneous rocks serve to heat slowly because it is difficult for water to penetrate into them.

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Cystic fibrosis is most common in individuals of Northern European descent, affecting 1 in 3200 newborns. Assuming that these al
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Answer:

0.0177

Explanation:

Cystic fibrosis is an autosomal recessive disease, thereby an individual must have both copies of the CFTR mutant alleles to have this disease. The Hardy-Weinberg equilibrium states that p² + 2pq + q² = 1, where p² represents the frequency of the homo-zygous dominant genotype (normal phenotype), q² represents the frequency of the homo-zygous recessive genotype (cystic fibrosis phenotype), and 2pq represents the frequency of the heterozygous genotype (individuals that carry one copy of the CFTR mutant allele). Moreover, under Hardy-Weinberg equilibrium, the sum of the dominant 'p' allele frequency and the recessive 'q' allele frequency is equal to 1. In this case, we can observe that the frequency of the homo-zygous recessive condition for cystic fibrosis (q²) is 1/3200. In consequence, the frequency of the recessive allele for cystic fibrosis can be calculated as follows:

1/3200 = q² (have two CFTR mutant alleles) >>  

q = √ (1/3200) = 1/56.57 >>

- Frequency of the CFTR allele q = 1/56.57 = 0.0177  

- Frequency of the dominant 'normal' allele p = 1 - q = 1 - 0.0177 = 0.9823

4 0
3 years ago
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