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3 years ago

10

Jonathan scored -2 on each of six golf holes what was his overall score for these six holes (HELP ME PLEASE AND THANK U)

2 answers:

kipiarov [429]3 years ago

7 0

Answer:

He score -12 for the 6 holes!!

Step-by-step explanation:

Hope this helps!! :))

Shtirlitz [24]3 years ago

4 0

Answer:

-12 is his overall score.

Step-by-step explanation:

-2 on each 6 holes...

-2 · 6 = -12

So, the overall score is -12

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Find the interquartile range (IQR) of the data in the box plot below. A horizontal boxplot titled Magnitude of earthquakes, is p

tresset_1 [31]

Answer:

IQR = 3

Step-by-step explanation:

Interquartile range, which is abbreviated as IQR, is just the difference between the upper quartile (where the box ends) and the lower quartile (where the box starts). AS it is given in the question that that box starts from 4 and ends at . The interquartile range IQR is simply:

IQR = 7 - 4 = 3

The values of data are usually clustured around some central value. Interquartile range tells us how spread out these middle values. It also tells when some values are too far from the central value. The values which are too far are also termed as outlier values

8 0

3 years ago

Read 2 more answers

Evaluate the expression. [(8 x 7) – 2): 9

frozen [14]

Answer:

☑ Answer is 6

Step-by-step explanation:

${ \tt{ \{(8 \times 7) - 2 \} : 9}} \\ = { \tt{(56 - 2) :9 }} \\ = { \tt{54 :9 }}$

» But this is a ratio, so it can be expressed in terms of fractions:

$= { \tt{ \frac{54}{9} }} \\$

» Divide both the denominator and numerator by 9:

${ \tt{ = \frac{54 \div 9}{9 \div 9} }} \\ \\ = { \tt{ \frac{6}{1} }} \\ \\ = 6$

6 0

3 years ago

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yuradex [85]

Answer:

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3 years ago

A train from Portland, Oregon, to Los Angeles, California, travels at an average speed of 60 miles per hour and covers a distanc

seropon [69]

Answer:

The train need to leave Portland at 03:27 am

Step-by-step explanation:

step 1

Find out how long it takes the train to travel from Portland, Oregon, to Los Angeles, California

Remember that

The speed is equal to divide the distance by the time

so

The time is equal to divide the distance by the speed

Let

s ---> the speed in miles per hour

d ---> the distance in miles

t ---> the time in hours

$t=\frac{d}{s}$

we have

$d=963\ mi$

$s=60\ mi/h$

substitute

$t=\frac{963}{60}=16.05\ hours$

step 2

Adds 30 minutes (time it takes to get from the train station to her aunt's house)

Remember that

$30\ minutes=0.50\ hours$

$16.05+0.50=16.55\ hours$

Convert to minutes

$16.55\ h=16.55(60)\ min=993\ min$

step 3

Remember that

$8 p.m=20:00\ hrs$

Convert to minutes

$20(60)=1,200\ min$

Subtract 993 minutes from 1,200 minutes

$1,200-993=207\ min$

Convert to hours+minutes

$207\ min=207/60=3.45\ hours$

$0.45\ h=0.45(60)=27\ min$

so

$3\ h+27\ min$

$00:00 + 03:27=03:27\ am$

therefore

The train need to leave Portland at 03:27 am

8 0

3 years ago

Find x. Round to the nearest degree.

jeka94

The Law of Cosines features the 3 side lengths of a triangle, plus the measure of the angle opposite one of those sides.

We want angle x, which is opposite the side of length 39.

Then: a^2 = b^2 - 2ab cos C becomes 39^2 = 36^2 + 59^2 - 2(36)(59)cos x

or 1521 = 3481 + 1296 - 2(36)(59) cos x

Subtract (3481+1296) from both sides: 1521 - 4777 = -4248cos x

-3256 = -4248cos x

-3256

Then: cosx = --------------- = 0.766

-4248

Solving for x: x = arccos -0.766 = 0.698 radian, or 40 degrees (answer)

5 0

3 years ago