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3 years ago

544ml^2 is how many litersshow your work

Mathematics

1 answer:

ivolga24 [154]3 years ago

7 0

Answer:

295.936

Step-by-step explanation:

First find out what 544^2 is. That is 295,936. There are 100 ml in 1 liter. So divide 295,936 by 100 to see how many liters are in 295,936 ml.

295,936÷100=295.936

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I dont understand this.

lakkis [162]

To find the area of a rectangle the formula is:

Area = length * height

A = L * H

In this case:

L = 3x

H = 2x

^^^In-put these values into the equation given above

A = 3x * 2x

Now you must multiply them together.

When multiplying numbers with variable(s) you multiply the number portion normally ( 3 * 2 = 6).

Multiplying variables is slightly different. The matching variables (x and x) will become one "x" and have an exponent attached to the x.

What will the exponent be? If a variable has no visible exponent it can be assumed that it has an exponent of 1. When multiplying variables the exponents on each variable will be sumed together and attached to the final variable:

$x^{1} *x^{1} = x^{1+1}$ = x²

Now combine the product of the numbers with the product of the variables:

Area = 6x²

Hope this helped!

~Just a girl in love with Shawn Mendes

8 0

4 years ago

1. A MAP SCALE READS 1CM:5KM. IF A DISTANCE ON THE MAP MEASURES 7CM, THE ACTUAL DISTANCE WILL BE?. 2. A SCHOOL DINING HALL IS 35

Agata [3.3K]

Answer:

1. 35 km

2. 1 cm to 5m

3. 6 cm

4. $42^\circ$

5. 16.73 m

Step-by-step explanation:

Solution 1.

Reading of map scale = 1cm:5km

i.e. 1 cm is equivalent to 5 km

Measurement of map = 7 cm

Actual distance = Measurement of map $\times 5$

Actual distance = 7 $\times 5$ = 35 km

-------------------

Solution 2.

Length of dining hall = 35 m

Measurement of map = 7 cm

Scale = Measurement of map : Length of dining hall (i.e. ratio)

Scale = 7 cm :35 m = 1 cm : 5 m

-------------------

Solution 3.

Length of building = 30 m

Scale = 1 cm to 5m

5 m is equivalent to 1 cm on scale

1 m is equivalent to $\frac{1}{5}$ cm on scale

30m is equivalent to $\frac{1}{5} \times 30$ = 6 cm on scale

-------------------

Solution 4.

Angle of elevation of A from B = $42^\circ$

Angle of depression of B from A = ?

Please refer to the image attached, we can clearly observe that both the angles (i.e. angle of elevation from A to B and angle of depression from B to A )will be equal.

Angle of depression of B from A = $42^\circ$

-------------------

Solution 5.

Given that:

String length, or hypotenuse of triangle BC= 25 m

Angle of string with horizontal, $\angle B = 42^\circ$