Answer:
a. P(male) = 0.4
b. P(no sport and male) = 0.1
c. Unclear question (isn't it the same as b.?)
Step-by-step explanation:
The data below is what I've worked according to, which isn't very clear from the question so the answers are only correct if this is the correct table of data;
![\left[\begin{array}{ccc}&No \ Sports&Sports\\Female&10&32\\Male&7&21\end {array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%26No%20%5C%20Sports%26Sports%5C%5CFemale%2610%2632%5C%5CMale%267%2621%5Cend%20%7Barray%7D%5Cright%5D)
a.

b.
Using the tree diagram in the picture;

Answer:
do 7/9*42. then you will get answer
Answer:
Hey, Dalilah. I hope I'm not too late, but the answer is <u><em>(3,5)</em></u>.
Step-by-step explanation:
You have to use the equation that includes the x value of <em>3</em>.
<em>4x+1</em> only includes x values that are less than <em>3</em>.
<em>2x-1</em> includes x values that are greater than or equal to <em>3</em>.
I plugged <em>3</em> into both of these equations <em>(4x+1; x < 3 & 2x-1; x ≥ 3)</em> in order to see which equation would've been true.
<em>4(3)+1 = 13; 13 < 3 [False] 13 isn't less than 3 -- and 2(3)-1 = 5; 5 ≥ 3 [True] 5 is greater than or equal to 3.</em>
Since the equation <em>2(3)-1; 5≥3</em> is true, you should use this equation. I used <em>Demos</em> in order to graph <em>Y=2(3)-1</em>. At the bottom of that I put <em>x=3</em>, and it showed me <em>(3,5)</em>.
I'll post the pictures for proof and better clarification if this is confusing, love.
Answer:
A and B
Step-by-step explanation:
Given


Required
Determine the appropriate combination
First, we need to determine the factors of 28 and 21


Next, is to bring out the similar traits in both factors


Represent both in terms of bag, we have:
1 bag of 28 nuts
7 bags of 4 nuts
1 bag of 21 dried fruits
7 bags of 3 dried fruits
This gives:
1 bag of 28 nuts and 1 bag of 21 dried fruits
7 bags of 4 nuts and 7 bags of 3 dried fruits
Hence:
<em>Option A and B are correct</em>