Approximately 2%. The reason is if you choose 20% and only have four with beef as the most popular, and approximately the number of restaurants is 15.
Answer:
12
Step-by-step explanation:
48/4=12 x=12
Answer:
3.2MULTIPLY10-8
Step-by-step explanation:BECUASE THERE IS A NEGATIVE SENSE AND WHEN YOU PRESS YOUR CALACULTAOR U WILL SEE IT TRY IT IF DONT UNDERSTAND LET ME KNOW AGAIN THANKS
Answer:
3(7 + 4)2 − 24 ÷ 6 = 62
Step-by-step explanation:
3(7 + 4)2 − 24 ÷ 6 is the given expression.
Now, by the rule of BODMAS, where B = Bracket, O= of, D = divide,
M = multiplication, A = addition and S = subtraction
we try and solve the following expression in the same order.
Solving the bracket first, we get
3<u>(7 + 4)</u>2 − 24 ÷ 6 = 3(<u>11</u>)2 − 24 ÷ 6 =<u> 66</u> − 24 ÷ 6
Next, we solve divide,
66 − <u>24 ÷ 6</u> = 66 - <u>4</u>
Next, solving the subtraction, 66 - 4 = 62
Hence, 3(7 + 4)2 − 24 ÷ 6 = 62
Answer:
See answer below
Step-by-step explanation:
The statement ‘x is an element of Y \X’ means, by definition of set difference, that "x is and element of Y and x is not an element of X", WIth the propositions given, we can rewrite this as "p∧¬q". Let us prove the identities given using the definitions of intersection, union, difference and complement. We will prove them by showing that the sets in both sides of the equation have the same elements.
i) x∈AnB if and only (if and only if means that both implications hold) x∈A and x∈B if and only if x∈A and x∉B^c (because B^c is the set of all elements that do not belong to X) if and only if x∈A\B^c. Then, if x∈AnB then x∈A\B^c, and if x∈A\B^c then x∈AnB. Thus both sets are equal.
ii) (I will abbreviate "if and only if" as "iff")
x∈A∪(B\A) iff x∈A or x∈B\A iff x∈A or x∈B and x∉A iff x∈A or x∈B (this is because if x∈B and x∈A then x∈A, so no elements are lost when we forget about the condition x∉A) iff x∈A∪B.
iii) x∈A\(B U C) iff x∈A and x∉B∪C iff x∈A and x∉B and x∉C (if x∈B or x∈C then x∈B∪C thus we cannot have any of those two options). iff x∈A and x∉B and x∈A and x∉C iff x∈(A\B) and x∈(A\B) iff x∈ (A\B) n (A\C).
iv) x∈A\(B ∩ C) iff x∈A and x∉B∩C iff x∈A and x∉B or x∉C (if x∈B and x∈C then x∈B∩C thus one of these two must be false) iff x∈A and x∉B or x∈A and x∉C iff x∈(A\B) or x∈(A\B) iff x∈ (A\B) ∪ (A\C).
