Answer:
20 gallons were used from the tank with the octane rating of 80.
Step-by-step explanation:
Given : One tank of gasoline has an octane rating of 140 and another tank of gasoline has an octane rating of 80. To obtain a mixture of 60 gallons with an octane rating of 120.
To find : How many gallons should be used from the tank with the octane rating of 80?
Solution : Let x be the volume of gas whose octane rating is 140 and
y be the volume of gas whose octane rating is 80.
Then, we form the equation as:
(1) 

or
.........[3]
(2) 
Now multiply equation (2) by 4
...........[4]
Subtract (4) from (3)



Put x in equation [4] we get,





Therefore, x=40 and y=20
So, 20 gallons were used from the tank with the octane rating of 80.
I am not sure about point slope, but I can find an equation in slope-intercept form and convert it, so
y=mx+b, m=slope
slope=(y1-y2)/(x1-x2)
we have points
(4,5)
(-3,-1)
(x,y)
x1=4
y1=5
x2=-3
y2=-1
subsitute
(5-(-1))/(4-(-3))=(5+1)/(4+3)=6/7
y=6/7+b
sybsitute and solve for b
(4,5)
x=4
y=5
5=6/7(4)+b
5=24/7+b
5=35/7
subtract 24/7 from both sides
11/7=b
y=6/7x+11/7
convert to the point slope form and find equivilent fraction
since the question asks for 2 answers that are correct and only 2 of the equations have slope of 6/7 I can guess that the answers are B and C
40 hundreds flats. 400 tens = 4,000. 40 hundreds also equals 4,000.
Answer:
c
Step-by-step explanation: