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2 years ago

15

If a round plate has a radius of 6 inches, what is the area of the plate

1 answer:

weeeeeb [17]2 years ago

7 0

113.04 about-ish I used 3.14 for pi

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Can you write for me some formula of log please? I have a pre-test tomorrow about that

Rasek [7]

Y = log(x-5) + log(x+5)

7 0

3 years ago

How to solve this showing all work ! Also explain why they aren’t polynomials if you can :)

Lesechka [4]

Polynomials are linear combinations of positive integer powers. For example,

$x^{100}+30x^2-\sqrt 2\,x+21$

is a polynomial, but

$-x^{-1}-4x^\pi+x^{3/2}$

is not.

(In case you're unfamiliar with the term, a linear combination of two quantities is the sum of scaled versions of those quantities, e.g. a general linear combination of $a$ and $b$ is $k_1a+k_2b$ , where $k_1,k_2$ are any numbers.)

$8x^2-18\sqrt x+5x-3$ is not a polynomial; the offending term is $-18\sqrt x$ , or $-18x^{1/2}$ .

7 0

2 years ago

At 6:00 PM, a flagpole that is 35 feet tall casts a shadow that is 50 feet long. At the same time, how long will a person's shad

sertanlavr [38]

<u>Answer:</u>

The length of the person’s shadow is 5.7ft

<u>Explanation:</u>

Length of the flagpole =a= 35ft

Length of the shadow of the flagpole= b=50ft

Length of the person=c= 4ft

Suppose the length of the person’s shadow is=d

According to the rules of trigonometry

$\frac{\text { Length of the flagpole }}{\text { Length of the shadow of the flagpole }}=\frac{\text { Length of the person }}{\text { Length of the person's shadow }}$

$\frac{a}{b}=\frac{c}{d}$

$\frac{35}{50}=\frac{4}{d}$

35d=200

d= $\frac{200}{35}$

d=5.7ft

Hence, The length of the person’s shadow is 5.7ft.

3 0

2 years ago

Find the equation of the line that is perpendicular to y = – 1 4 x – 8 and passes though the point (2, –4).

vivado [14]

The equation of the line is $y=\frac{1}{4}x-\frac{29}{7}$

Explanation:

The equation of the line is perpendicular to $y=-14 x-8$

The equation is of the form $y=mx+b$ where m=-14

<u>Slope:</u>

The slope of the perpendicular line can be determined using the formula,

$m_1 \cdot m_2=-1$

$-14 \cdot m_2=-1$

$m_2=\frac{1}{14}$

Thus, the slope of the line is $m=\frac{1}{14}$

<u>Equation of the line:</u>

The equation of the line can be determined using the formula,

$y-y_1=m(x-x_1)$

Substituting the slope $m=\frac{1}{14}$ and the point (2,-4), we get,

$y+4=\frac{1}{14}(x-2)$

Simplifying, we get,

$y+4=\frac{1}{14}x-\frac{1}{7}$

$y=\frac{1}{14}x-\frac{1}{7}-4$

$y=\frac{1}{4}x-\frac{29}{7}$

Thus, the equation of the line is $y=\frac{1}{4}x-\frac{29}{7}$

3 0

2 years ago

The zero of the function in A(x)=9x^2-25/3x+5 is <br><br> A. -5/3<br> B. 5/3<br> C. 5

trapecia [35]

it took me a while but the answer is 5/3

3 0

2 years ago

Read 2 more answers