(3x + 3) (2x − 2) Please help me

Mathematics

1 answer:

kupik [55]3 years ago

8 0

The answer is 6(x^2 -1) I have provided a picture with my work and the answer

You might be interested in

Olivia is making cupcakes for her class. She needs to make 15 cupcakes in all. Each cupcake requires 1/3 cup of batter and 1/4 c

Studentka2010 [4]

Answer:5 cups of batter and 3 3/4 cups of icing

Step-by-step explanation:

15× 1/3= 5 cups batter and 15×1/4= 3 3/4

3 0

3 years ago

5.2.8. Suppose K1 and K2 are positive definite n × n matrices. Suppose that, for i = 1, 2, the minimizer of pi (x) = xTKix − 2xT

Svet_ta [14]

Answer:

Q7 if you multiplying matrix K1 and K2.The number of items on the row of K1 must be equal to the number of items on the columns of matrix K2 if not it's not applicable.

Step-by-step explanation:

7 0

3 years ago

Help :) ill mark as brainliest.

CaHeK987 [17]

Answer:

C. 3,386,880 yd^3

Step-by-step explanation:

5 0

4 years ago

Read 2 more answers

Find the value of x. Round to the nearest tenth.

denpristay [2]

Answer:

$\displaystyle x \approx 38.2 ^{\circ}$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtract Property of Equality

Pre-Calculus

Law of Sines: $\displaystyle \frac{sin(A)}{a} =\frac{sin(B)}{b} =\frac{sin(C)}{c}$

A, B, C are angle measures
a, b, c are leg lengths

Step-by-step explanation:

Step 1: Identify

A = 27°, a = 11

B = x°, b = 15

Step 2: Solve for x

Substitute [LOS]: $\displaystyle \frac{sin(27^{\circ})}{11} =\frac{sin(x^{\circ})}{15}$
Cross-multiply: $\displaystyle 11sin(x^{\circ}) = 15sin(27^{\circ})$
Isolate x term: $\displaystyle sin(x^{\circ}) = \frac{15sin(27^{\circ})}{11}$
Isolate x: $\displaystyle x = sin^{-1}(\frac{15sin(27)}{11})$
Evaluate: $\displaystyle x = 38.2488 ^{\circ}$
Round: $\displaystyle x \approx 38.2 ^{\circ}$