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Leona [35]
3 years ago
6

Plot and connect the points A (-4, -5), B (-2, -3), C (4, -3), D (6, -2), E (6, 6), F (-1, 6), G (-4, 2), and find the length of

EF.
Mathematics
1 answer:
Vinvika [58]3 years ago
5 0

Answer:

Its 3 triangles that are connected!

Step-by-step explanation:

The 3 points of the <u><em>FIRST TRIANLE</em></u>  (closest to the left side of the page) has the points of -4, 2 and -4, -5 and -2, -3.

The 2 points of the <u><em>SECOND TRIANGLE</em></u>(connected to the first triangle and third triangle,.... and the third triangle makes the second triangle possible!!) and the points are -2, -3 and -1, -6

The 4 points to the <u><em>THIRD TRIANGLE</em></u> (The closest to the right side of the page) the points are 6, 6 and 6, -2 and 4, -3 and 1, -6

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Help pls with math lotsss of points!!!
sveticcg [70]

Answer:

5x^2+22x-12         x cannot be -5, -4, -2

(x+5)(x+4)(x+2)

Step-by-step explanation:

In order to solve this, your denominator must be the same. Let's start by writing out the two different quadratic formulas:

x^2 + 6x + 8 <-- This should factor out to (x+4)(x+2)

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Now that you have factored out the two quadratics, plug them into the equation.

    5x        -       3

(x+4)(x+2)      (x+5)(x+2)

Now as we know, -2 cannot be x because it will turn the entire equation undefined. Multiple top and bottom with (x+5) on the right side and (x+4) on the left side.

5x (x+5)             -           3(x+4)  

(x+5)(x+4)(x+2)      (x+5)(x+4)(x+2)

Focus on the top. 5x(x+5) will turn out to be 5x^2+25x. 3(x+4) will turn out to be 3x+12. Combine the two equations because now they are equal to each other and do the subtraction:

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 (x+5)(x+4)(x+2)               (x+5)(x+4)(x+2)

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Among all right circular cones with a slant height of 24​, what are the dimensions​ (radius and​ height) that maximize the volum
aleksklad [387]

Answer:

5571.99

Step-by-step explanation:

We need to use the Pythagorean theorem to solve the problem.

The theorem indicates that,

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Once this is defined, we proceed to define the volume of a cone,

v=\frac{1}{3}\pi r^2 h

Substituting,

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We need to find the maximum height, so we proceed to calculate h, by means of its derivative and equalizing 0,

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<em>We select the positiv value.</em>

We have then,

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We can now calculate the maximum volume,

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3 years ago
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