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aliina [53]
3 years ago
15

Please I need a partner. Will give 25 points!,!!

Mathematics
2 answers:
yawa3891 [41]3 years ago
7 0

Answer:

a partner for what tho?

Step-by-step explanation:

dmitriy555 [2]3 years ago
3 0
1st row - A: 2 ft in one year, B: 1/2 of a year (or 3/6)(or 6 months)
2nd row - A: 1 1/2 in one hour (or 12/8), B: 8/12 of an hour (or 2/3)(or 40 minutes)
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For Normal distribution with mean u 400
taurus [48]

Answer:

Step-by-step explanation:

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the weights of a population, and for this case we know the distribution for X is given by:

 

Where  and

We are interested on this probability

And the best way to solve this problem is using the normal standard distribution and the z score given by:

If we apply this formula to our probability we got this:

And we can find this probability using the normal standard table or exce:

answer

4 0
3 years ago
How do u solve a=b+3(4-c)​
mario62 [17]

Answer:

5+3(4-2)

5+3x2

5+6

11

the answer is 11

Step-by-step explanation:

8 0
4 years ago
Read 2 more answers
Simplify the first trigonometric expression by writing the simplified form in terms of the second expression (1/1-cosx)-(cos/1+c
garik1379 [7]

(\frac{1}{1-cos(x)})-(\frac{cos(x)}{1+cos(x)})

cscx is  1/sinx

maybe they want us to use pythagorean identity

cos^2(x)+sin^2(x)=1

I notice we have 1-cos(x) and 1+cos(x), if we multiply them, we get 1-cos^2(x)

and if we look at the pythagorean identity and minus cos^2(x) from both sides, we get

sin^2(x)=1-cos^2(x)

since csc(x)=\frac{1}{sin(x)}, csc^2(x)=\frac{1}{sin^2(x)}=\frac{1}{1-cos^2(x)}

(recall that (a-b)(a+b)=a²-b²)

match the denomenators of the original fraction

multiply first fraction by \frac{1+cos(x)}{1+cos(x)} and the 2nd by \frac{1-cos(x)}{1-cos(x)}


(\frac{1+cos(x)}{1-cos^2(x)})-(\frac{cos(x)(1-cos(x))}{1-cos^2(x)})=

((csc^2(x))(1+cos(x)))-((csc^2(x))(cos(x)-cos^2(x)))=

csc^2(x)+csc^2(x)cos(x)-(csc^2(x)cos(x)-csc^2(x)cos^2(x)=

csc^2(x)+csc^2(x)cos(x)-csc^2(x)cos(x)+csc^2(x)cos^2(x)=

csc^2(x)+csc^2(x)cos^2(x)=

csc^2(x)(1+cos^2(x)), hmm, to get ride of those cos(x)

look to the pythagorean identity again


sin^2(x)+cos^2(x)=1, force one side into form 1+cos^2(x)

1+cos^2(x)=2-sin^2(x), recall that since csc(x)=1/sin(x), sin(x)=1/csc(x) and sin^2(x)=1/(csc^2(x))

1+cos^2(x)=2-\frac{1}{csc^2(x)}

subsituting


csc^2(x)(1+cos^2(x))=

(csc^2(x))(2-\frac{1}{csc^2(x)})= distributing

2csc^2(x)-\frac{csc^2(x)}{csc^2(x)}=

2csc^2(x)-1 is the simplified expression

8 0
3 years ago
–h − 17 = 19 + h<br> h= ?
mixer [17]
- h - 17 = 19 + h
-2h = 36
h = -18

Hope this helps!!
8 0
3 years ago
Read 2 more answers
1.) The individual letters of the word CLASSICALLY are written on pieces of paper and placed in a hat. One letter is selected at
Dennis_Churaev [7]

Answer:

1.) 9/11

2.)13/70

3.)the number would increase by 2%

Step-by-step explanation:

5 0
3 years ago
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