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jekas [21]
3 years ago
12

A line passes through the point (-6, -2) and has a slope of -5/2

Mathematics
2 answers:
creativ13 [48]3 years ago
7 0

Answer:

y = (-5/2)x - 17

Step-by-step explanation:

<h2>Slope Intercept Formula:</h2>

y = mx + b

m = slope

b = y-intercept

<h2>Plugin Information:</h2>

y = mx + b

Slope = -5/2

y = (-5/2)x + b        \longmapsto\\         Input x and y values from given point

-2 = (-5/2)-6 + b

<h2>Simplify, Solve for b:</h2>

-2 = (-5 * -6)/(2) + b

-2 = 30/2 + b

-2 = 15 + b

b = -2 - 15

b = -17

<h2 /><h2>Rewrite Equation:</h2>

y = mx + b

m = -5/2

b = -17

y = (-5/2)x - 17

-Chetan K

-Chetan K

Darya [45]3 years ago
4 0

Answer: y = -5/2 -17

Step-by-step explanation: First put the equation in point slope form

Y-y1 = m(x-x1)

y + 2 = -5/2(x+6) then simplify to slope int. form

Y= mx + b

Y = -5/2x-17

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