QUESTION:
The code for a lock consists of 5 digits (0-9). The last number cannot be 0 or 1. How many different codes are possible.
ANSWER:
Since in this particular scenario, the order of the numbers matter, we can use the Permutation Formula:–
- P(n,r) = n!/(n−r)! where n is the number of numbers in the set and r is the subset.
Since there are 10 digits to choose from, we can assume that n = 10.
Similarly, since there are 5 numbers that need to be chosen out of the ten, we can assume that r = 5.
Now, plug these values into the formula and solve:
= 10!(10−5)!
= 10!5!
= 10⋅9⋅8⋅7⋅6
= 30240.
Answer:
d= (-11-2)^2 + (-12--12)^2
d= (-13)^2 + (0)^2
d=169
square root the 169
answer is 13
that's the distance from (2, -12) (-11, -12)
hope that helps
Step-by-step explanation:
Answer:
31.5 units^2
Step-by-step explanation:
Rectangle area (RA) = l × w
Triangle area (TA) = (bh)/2
RA = 3 × 7
RA = 21
TA = (7 × 3)/2
TA = 21/2
TA = 10.5
(Triangles are congruent as shown by the lines on each side of the triangle so I can calculate area of both of them together as I just did)
Add areas together
21 + 10.5 = 31.5
Answer:
$0.41
Step-by-step explanation:
1 ice cream cone: $2.75
2 ice cream cones: 2 * $2.75 = $5.50
7.5% of $5.50 =
= 0.075 * $5.50
= $0.4125
Answer: $0.41
