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Leto [7]
3 years ago
11

(b) The mean score for a class sitting a Physics test is 46, with stan- dard deviation of 4. The mean score for the same class i

n a Chem- istry test is 77, with standard deviation of 9. Each set of scores is normally distributed. Which is more likely: a student gets over 90 on the Chemistry test, or over 52 on the Physics test? [7 marks
Mathematics
1 answer:
daser333 [38]3 years ago
4 0

Answer:

Step-by-step explanation:

Let X be the mean score for physics test, and Y be the mean score for Chemistry test

Given that X is normal N(46,4)

Y is N(77,9)

when y>52 and x >90 to compare we have to convert these into corresponding Z scores

x>52⇒z>\frac{52-46}{4} \\z>1.5

For y>90, \\Z>\frac{90-77}{9} =1.444

Since Z>1.444 has more area than z>1.5 we find that it is more likely that

a student gets over 90 on the Chemistry test

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Answer:

1. f(g(4)) - g(f(4)) = -6

2. f(f(x)) = 125x^4 - 250x^2 + 120

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Step-by-step explanation:

1.

First we need to find f(4) and g(4):

f(4) = 4 + 3 = 7

g(4) = 3*4 + 5 = 17

Then, we find g(f(4)) = g(7):

g(7) = 3*7 + 5 = 26

And we find f(g(4)) = f(17):

f(17) = 17 + 3 = 20

so f(g(4)) - g(f(4)) = 20 - 26 = -6

2.

To find f(f(x)), we use the value of f(x) for every x in f(x):

f(f(x)) = 5*(f(x))^2 - 5 = 5*(5x^2 - 5)^2 - 5 = 5*(25x^4 - 50x^2 + 25) - 5

f(f(x)) = 125x^4 - 250x^2 + 120

3.

To find f(g(x)), we use the value of g(x) for every x in f(x):

f(g(x)) = g(x) + 6 = ax + b + 6 = 3x + 3

ax + (b+6) = 3x + 3 -> a = 3 and b = -3

a + b = 3 - 3 = 0

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If we assume g(x) = ax + b, we have:

g(f(x)) = a*(2x - 3) + b = 2ax - 3a + b = 5 - 4x

2a = -4 -> a = -2

-3a + b = 5

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3 years ago
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Answer:

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