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3 years ago

Convert improper fraction to a mixed number 9/2

1 answer:

8 0

2 goes into 9 4 times. So 4 is your large number and you have 1 remaining, put that over the denominator and your answer is 4 1/2

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If y = 4.5 when x = 2.5, find y when x = 12.

hichkok12 [17]

4.5/2.5 = y/12
y = 12 * 4.5/2.5
y = 21.6

3 0

3 years ago

I badly need help with this!!! Pls pls help, thank you

stiv31 [10]

Answer:

<em>DAC=18(corresponding angles)</em>

<em>EAD= 162 degrees</em>

Step-by-step explanation:

<em>DAC=18(corresponding angles)</em>

EAD=180-18(angles on a straight line)

<em>EAD= 162 degrees</em>

8 0

2 years ago

Read 2 more answers

In a poll, 1,004 adults in a certain country were asked whether they favor or oppose the use of "federal tax dollars to fund m

WARRIOR [948]

Answer:

The range of values likely to contain the true value of the population parameter is between 44% and 52%.

Step-by-step explanation:

Confidence interval concepts:

A confidence interval has two bounds, a lower bound and an upper bound.

These bounds are dependent of the sample mean and of the margin of error.

The lower bound is the sample mean subtracted by the margin of error, while the upper bound is the margin of error added to the sample mean.

The confidence interval is likely to contain the true value of the population parameter.

In this question:

Sample mean: 48%

Margin of error: 4%

48 - 4 = 44%

48 + 4 = 52%

The range of values likely to contain the true value of the population parameter is between 44% and 52%.

7 0

3 years ago

Taylor was asked to solve the system of linear equations

yarga [219]

Id take a guess and say line 1 because the rest looks correct

4 0

3 years ago

26. Students who take a statistics course are given a pre-test on the concepts and skills for the first chapter of a statistics

hjlf

The test statistic value lies to the right of the critical value. So we have sufficient evidence to reject the null hypothesis.

<h3>What are null hypotheses and alternative hypotheses?</h3>

In null hypotheses, there is no relationship between the two phenomenons under the assumption or it is not associated with the group. And in alternative hypotheses, there is a relationship between the two chosen unknowns.

Students who take a statistics course are given a pre-test on the concepts and skills for the first chapter of a statistics course.

Then they are given a post-test once the professor has concluded lecturing on the material.

Pre-test and post-test scores for 4 students in an elementary statistics class are given below.

Then we have

$\mu _d = \mu _{post} - \mu _{pre}$

Then the null hypotheses and alternative hypotheses will be

H₀: $\mu _d = 0$

Hₐ: $\mu _d > 0$

Then the test statistic will be

$\rm \overline{x} _d = \dfrac{\Sigma x_d}{n} = \dfrac{15+12+10+1}{4}\\\\\overline{x} _d = 9.5$

Then

$\rm S_d = 6.02$

The test statistic value is given by

$\rm t = \dfrac{\overline{x} _d }{\dfrac{S_d}{\sqrtn}} \\\\t = \dfrac{9.5}{\dfrac{6.02}{\sqrt4}}\\\\t = 3.16$

Since this is a right-tailed test, so the critical value is given by

$\rm t_{n-1}(\alpha ) = t_3 (0.05) = 2.353$

Since the test statistic value lies to the right of the critical value. So we have sufficient evidence to reject the null hypothesis.

Hence, we can conclude that $\mu _d > 0$ that is test scores have improved.

More about the null hypotheses and alternative hypotheses link is given below.

brainly.com/question/9504281

#SPJ1

7 0

2 years ago