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Romashka-Z-Leto [24]
4 years ago
7

Area of 2 1/4 by 3 1/2

Mathematics
2 answers:
vovangra [49]4 years ago
3 0
Hey there!

2 1/4 = 9/4

3 1/2 = 7/2

9 x 7 = 63

4 x 2 = 8

= 63/8

Simplifying 63/8 . . .

63/8 = 7 7/8

2 1/4 * 3 1/2 = 7 7/8

Area = 7 7/8

I hope this helps you!
melomori [17]4 years ago
3 0
\boxed {\boxed {\text {Area = Length x Width}}}

\text {Area =} 2 \dfrac{1}{4}  \times 3 \dfrac{1}{2}

\text {Area =} \dfrac{9}{4}  \times \dfrac{7}{2}

\text {Area =} \dfrac{63}{8}

\text {Area =} 7\dfrac{7}{8} \text { units}^2
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COLLEGE ALGEBRA!!!!
Savatey [412]

Answer:

a.A_t=A_o.(\frac{1}{2})^t^/^{t_h}

b. 0.010986grams

c.109.84 mins

Step-by-step explanation:

Let  t_1_/_2 denote the half life of our substance t to be our time, A_t is mass at time t and A_o as initial mass. Our half life equation can be expressed as:

A_t=A_o.(\frac{1}{2})^t^/^{t_h} from which we can obtained mass at any given time.

b. From our equation above,

we can convert our t into mins as t=4*60=240mins

We then substitute t value into the equation

A_2_4_0=45\times(1/2)^2^4^0^/^2^0\\=0.010986\\=0.010986grams

Hence mass after 4hrs is 0.010986grams

c. We can set our final mass to 1g  then substitute in the equation

A_t=A_o.(\frac{1}{2})^t^/^{t_h}. Substitute A_t=1g

1.0=45\times(1/2)^t^/^20

1.0=45\times(1/2)^t^/^2^0\\log(1/45)=(t/20)\times log(1/2)\\t=20\times5.491853=109.84 mins

Hence time until 1g mass is 109.83 minutes

5 0
3 years ago
How do you estimate $27.64 ×3 by using compatible numbers?
Natasha_Volkova [10]
Compatible numbers are numbers that are close to the numbers they're replacing that divide evenly into each other
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3 0
4 years ago
A DJ has a total of 1075 dance and rock songs on her system. The dance selection is 4 times the size of the rock selection. Writ
KIM [24]

Answer:

Write a system of equations to represent the situation.

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r: Number of rock songs

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4 0
3 years ago
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Ivanshal [37]

Answer:

h = 11/9 or 1 2/9

Step-by-step explanation:

(-5/11)h+(7/9)=(2/9)

(-5/11)h=(2/9)-(7/9)

(-5/11)h=(-5/9)

h = (-5/9)(-11/5)

h = 11/9

or

h = 1 2/9


5 0
3 years ago
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y

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80

0

81

1

80

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77

xy-277-180081180277

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Direction: Opens Down

Vertex:  

(

0

,

81

)

(0,81)

Focus:  

(

0

,

323

4

)

(0,3234)

Axis of Symmetry:  

x

=

0

x=0

Directrix:  

y

=

325

4

y=3254

x

y

−

2

77

−

1

80

0

81

1

80

2

77

xy-277-180081180277

f

(

x

)

=

8

1

−

x

2

?

?

f(x)=81-x2??

f

(

x

)

=

81

−

x

2

x

?

f(x)=81-x2x?

f

(

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=

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x

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f(x)=81-x2x2?

f

(

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=

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x

3

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f(x)=81-x2x3?

(

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|

[

]

√



≥





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π



7

8

9

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(

0

,

81

)

(0,81)

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(

0

,

323

4

)

(0,3234)

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x

=

0

x=0

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325

4

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Select a few  

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x

y

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2

77

−

1

80

0

81

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80

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xy-277-180081180277

Graph the parabola using its properties and the selected points.

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(

0

,

81

)

(0,81)

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(

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,

323

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Axis of Symmetry:  

x

=

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x=0

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4

y=3254

x

y

−

2

77

−

1

80

0

81

1

80

2

77

xy-277-180081180277

f

(

x

)

=

8

1

−

x

2

?

?

f(x)=81-x2??

f

(

x

)

=

81

−

x

2

x

?

f(x)=81-x2x?

f

(

x

)

=

81

−

x

2

x

2

?

f(x)=81-x2x2?

f

(

x

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=

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−

x

2

x

3

?

f(x)=81-x2x3?

(

)

|

[

]

√



≥







π



7

8

9

Direction: Opens Down

Vertex:  

(

0

,

81

)

(0,81)

Focus:  

(

0

,

323

4

)

(0,3234)

Axis of Symmetry:  

x

=

0

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Axis of Symmetry:  

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−

x

2

x

?

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(

x

)

=

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−

x

2

x

2

?

f(x)=81-x2x2?

f

(

x

)

=

81

−

x

2

x

3

?

f(x)=81-x2x3?

(

)

|

[

]

√



≥







π



7

8

9

Direction: Opens Down

Vertex:  

(

0

,

81

)

(0,81)

Focus:  

(

0

,

323

4

)

(0,3234)

Axis of Symmetry:  

x

=

0

x=0

Directrix:  

y

=

325

4

y=3254

Select a few  

x

x

values, and plug them into the equation to find the corresponding  

y

y

values. The  

x

x

values should be selected around the vertex.

Tap for more steps...

x

y

−

2

77

−

1

80

0

81

1

80

2

77

xy-277-180081180277

Graph the parabola using its properties and the selected points.

Direction: Opens Down

Vertex:  

(

0

,

81

)

(0,81)

Focus:  

(

0

,

323

4

)

(0,3234)

Axis of Symmetry:  

x

=

0

x=0

Directrix:  

y

=

325

4

y=3254

x

y

−

2

77

−

1

80

0

81

1

80

2

77

xy-277-180081180277

f

(

x

)

=

8

1

−

x

2

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f(x)=81-x2??

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x

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=

81

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x

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x

2

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f(x)=81-x2x2?

f

(

x

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=

81

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x

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3

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(

)

|

[

]

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5 0
3 years ago
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