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Semmy [17]
3 years ago
15

Please I need help ASAP

Mathematics
1 answer:
DIA [1.3K]3 years ago
3 0

Answer:

yes

Step-by-step explanation:

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7 0
3 years ago
The figure shows a person estimating the height of a tree by looking at the
FrozenT [24]

Answer:

The proportion that can be used to estimate the height of the tree is option;

A. \dfrac{h}{12} = \dfrac{6}{5}

Step-by-step explanation:

The given parameters in the question are;

The medium through which the person looks at the top of the tree = A mirror

The angle formed by the person and the tree with the ground = Right angles = 90°

The distance of the person from the mirror, d₁ = 5 ft.

The height of the person, h₁ = 6 ft.

The distance of the tree from the mirror, d₂ = 12 ft.

The angle formed by the incident light from the tree on the mirror, θ₁ = The angle of the reflected light from the mirror to the person, θ₂

Let 'A', 'B', 'M', 'T', and 'R' represent the location of the point at the top of the person's head, the location of the point at the person's feet, the location of the mirror, the location of the top of the tree and the location of the root collar of the tree, we have;

TR in ΔMRT = The height of the tree = h, and right triangles ΔABM and ΔMRT are similar

The corresponding legs are;

The height of the person and the height of the tree, which are AB = 6 ft. and TR = h, respectively

The distances of the person and the tree from the mirror, which are BM = 5 ft. and MR = 12 ft. respectively

∴ The angle formed by the incident light from the tree on the mirror, θ₁ = ∠TMR

The angle of the reflected light from the mirror to the person, θ₂ = ∠AMB

Given that θ₁ = θ₂, we have;

tan(θ₁) = tan(θ₂)

∴ tan(∠TMR) = tan(∠AMB)

tan\angle X = \dfrac{Opposite \ leg \ length \ to \ reference \ angle}{Adjacent \ leg \ length \ to \ reference \ angle}

tan(\angle TMR) = \dfrac{TR}{MR} = \dfrac{h}{12}

tan(\angle AMB) = \dfrac{AB}{BM} = \dfrac{6}{5}

From tan(∠TMR) = tan(∠AMB), we have;

\dfrac{h}{12} = \dfrac{6}{5}

\therefore h = \dfrac{6 \, ft.}{5 \, ft.} \times 12 \, ft. = 14.4 \, ft.

The height of the tree, h = 14.4 ft.

Therefore, from the proportion \dfrac{h}{12} = \dfrac{6}{5} the height of the tree can be estimated.

3 0
3 years ago
Explain the steps used in this equation! Please help I will give brainliest to whoever answers ✌️✌️✌️✌️✌️
jekas [21]

Answer:

Step-by-step explanation:

3(x+4)-6=5x+5

distribute 3 through the parenthesis (3 times x + 3 times 4)=3x+12

3x+12-6=5x+5

subtract 12-6

3x+6=5x+5

Move the variable to the left and change the sign

3x-5x+6=5

collect like terms

3x-5x=5-6

-2x=5-6

divide both sides by -2

x=1/2

4 0
3 years ago
What is the probability of drawing a 3 on a die twice?
umka21 [38]
At least a 1 out of 6
6 0
3 years ago
14. A boy is standing on the top of a tower, observed that the angle of depression of a car on the horizontal ground is 60". On
qaws [65]

The height of the tower is 331.3 meters

The distance from the car to the foot of the tower is 191.3 meters

The situation forms a right angle triangle.

<h3>Right angle triangle:</h3>

Right angle triangle has one of its angles as 90 degrees. Therefore,

The height of the tower is the opposite side of the right angle triangle. The distance from the foot of the tower to the car is the adjacent side of the triangle formed.

Therefore, the following trigonometric can be formed from the relationship.

let

x = adjacent side = distance from the foot of the tower to the car.

Therefore,

x=\frac{140 + h}{tan60}=\frac{h}{tan45}

cross multiply,

(140 + h)(tan 45) = h tan 60

140 tan 45 + h tan 45 = h tan 60

140 tan 45  =  h tan 60 -  h tan 45

140 = h√3 - h

140 = 1.732h - h

140 = 0.732h

h = 140 / 0.732

h = 191.256830601

h = 191.3

Therefore,

height of the tower = 140 + 191.3 = 331.3

The distance from the car to the foot of the tower is as follows;

  • x = 191.3 / tan 45

x = 191.3 / 1

x = 191.3

Therefore, the distance from the car to the foot of the tower is 191.3 meters

learn more on right triangle here; brainly.com/question/26750565?referrer=searchResults

3 0
3 years ago
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