First we will find the total measure of the second base.
Second base is extended more so that meas it will measure extended part plus the first base.
Second base = 7 + 5 = 12.
Now for the area.
A = 1/2(b1+b2)(h)
A = 1/2(7 + 12)(7)
A = 66.5
The area is 66.5 ft²
Hope this helps :)
6 - 3 = 3
5/6 - 1/3 = 5/6 - 2/6 = 3/6 = 1/2
answer is : 3 1/2 ( or 7/2)
Answer:
A: The solution to this system is no viable because it results in fractional values of tickets
Step-by-step explanation:
Let number of adult, child, and senior tickets be x, y and z respectively.
Thus;
x + y + z = 12 - - - (eq 1)
she purchases 4 more child tickets than senior tickets.
Thus, y = z + 4
Thus:
x + (z + 4) + z = 12
x + 2z + 4 = 12
x + 2z = 8 - - - (eq 2)
Also, We are told that Adult tickets are $5 each, child tickets are $2 each, and senior tickets are $4 each. She spends a total of $38,
Thus;
5x + 2(z + 4) + 4z = 38
5x + 2z + 8 + 4z = 38
5x + 6z + 8 = 38
5x + 6z = 38 - 8
5x + 6z = 30
Divide through by 5 to get;
x + (6/5)z = 6 - - - (eq 3)
Subtract eq 2 from eq 1 to get;
2z - (6/5)z = 8 - 6
2z - (6/5)z = 2
Multiply through by 5 to get;
10z - 6z = 10
4z = 10
z = 2½
It's not possible to have a fractional value of a ticket and thus we can say that the solution is not viable.
No it is not. Anything in the shaded area is a solution m. (4,3) is not in the shaded area so it is not a solution for the graphed inequality.
Answer:c
Step-by-step explanation:
