So, the slope is -3/5, and the y axis is unidentified.
A point is located at (6,-5). We will use this point.
In order to get the y-axis, we will use 5 from the slope because the denominator allows us to move left and right.
We will also use 6 from the point to give us a dot in the x-coordinate.
We will then divide 5 from the 6 to give us how much we have to go up or down
6/5
We will then use the -3 in the slope.
We will times -3 to the 6/5 in order to know how much we have go up or down.
-18/5 + 5 (from the point)((and since we are moving back, we will add a negative) (My problem))= 1 2/5 (y-intercept)
y = -3/5x + 1 2/5
The y = 13, we will plug it in the equation.
13 = -3/5x + 1 2/5 (subtract 1 2/5 on both sides)
11 3/5 = -3/5x (times 5 on both sides)
-3x = 58 (divide -3 on both sides)
x = -58/3
