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3 years ago

Dividing and Multiplying functions

1 answer:

4 0

Ok, so first of all, you need to plug the functions into their places. Since f(x) = 6x and g(x) = x + 3, you'll plug them in accordingly:
(6x) * (x + 3).

Then you'll multiply them together to get 6x^2 + 18x. You can't combine like terms then because of the square in the first term.

So your final answer is 6x^2 + 18x.

I hope this helps you at least a little bit. Thanks for your time!

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Change a Relation to Make It a Function The relation R is shown below as a list of ordered pairs. R = { (1, 4), (1, 3), (-1, 3),

nexus9112 [7]

Answer: (1,4) and (1,3) because the have the same x-value

Step-by-step explanation:

A function is defined so that for each input (known as the domain), there is no more than one output (known as the range).

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1 year ago

What numbers can i add to equal 17

Kay [80]

1+16
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9+8
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3 years ago

If c (x) = StartFraction 5 Over x minus 2 EndFraction and d(x) = x + 3, what is the domain of (cd)(x)?

Volgvan

Answer:

The domain of the function (cd)(x) will be all real values of x except x = 2.

Step-by-step explanation:

The two functions are $c(x) = \frac{5}{x - 2}$ and d(x) = x + 3

So, (cd)(x) = $(\frac{5}{x - 2})(x + 3) = \frac{5(x + 3)}{x - 2}$

Then, for x = 2 the function (cd)(x) will be undefined as zero in the denominator will make the function (cd)(x) undefined.

Therefore, the domain of the function (cd)(x) will be all real values of x except x = 2. (Answer)

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3 years ago

Read 2 more answers

Write the following precent as a decimal 1/8%

Serggg [28]

Answer:

.125

Step-by-step explanation: To convert 1/8 to a decimal, divide the denominator into the numerator. 1 divided by 8 = . 125. To convert the decimal .

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2 years ago

Read 2 more answers

2^x=3^x+1 what are the exact approximate solutions

Mashcka [7]

Answer:

Step-by-step explanation:

The goal of course is to solve for x. Right now there are 2 of them, one on each side of the equals sign, and they are both in exponential positions. We have to get them out of that position. The way we do that is by taking the natural log of both sides. The power rule then says we can move the exponents down in front.

$ln(2^x)=ln(3^{x+1})$ becomes, after following the power rule:

x ln(2) = (x + 1) ln(3). We will distribute on the right side to get

x ln(2) = x ln(3) + 1 ln(3). The goal is to solve for x, so we will get both of them on the same side:

x ln(2) - x ln(3) = ln(3). We can now factor out the common x on the left to get:

x(ln2 - ln3) = ln3. The rule that "undoes" that division is the quotient rule backwards. Before that was a subtraction problem it was a division, so we put it back that way and get:

$x(\frac{ln(2)}{ln(3)})=ln(3)$ . We can factor out the ln from the left to simplify a bit:

$x[ln(\frac{2}{3})]=ln(3)$ . Divide both sides by ln(2/3) to get the x all alone:

$x=\frac{ln(3)}{ln(\frac{2}{3}) }$

On your calculator, you will find that this is approximately -2.709

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3 years ago