Answer:
I wish I knew this maybe use the brainy scanner it could help you or google.
Tanα=h/x, tanß=h/(x+88)
solving both for x
x=h/tanα, x=h/tanß-88, since x=x
h/tanα=h/tanß-88
h/tanß-h/tanα=88
(htanα-htanß)/(tanα*tanß)=88
h(tanα-tanß)/(tanα*tanß)=88
h=88(tanα*tanß)/(tanα-tanß)
Since α=32 and ß=22...
h=88(tan32*tan22)/(tan32-tan22)
h≈85.3 feet
Answer:
The triangle has one solution. The remaining side c ≈ 4 and remaining angles B = 30°; C = 31°.
Option D is correct.
Step-by-step explanation:
if angle A is obtuse and if a > b then the triangle has one solution
We are given ∠ = 119° which is obtuse and side a= 7 and side b - 4 i.e 7>4 so, the triangle has one solution.
Finding remaining side c and ∠B and ∠C
Using Law of sines to find ∠B
a/sin A = b/sin B
7/sin 119° = 4/sin B
7 * sin B = 4 * sin 119
7*sin B = 4(0.874)
sin B = 3.496/7
B = sin^-1(0.4994)
B = 29.96 = 30°
We know that sum of angles of triangle = 180°
So, 180° = 119° + 30° +∠C
180° = 149° + ∠C
=> ∠C = 180° - 149°
∠C = 31°
Now finding c
b/sin B = c /sin C
4/Sin 30 = c/sin 31
4* sin 31 = c*sin 30
4*0.515 = c* 0.5
=> c = 4*0.515/0.5
c = 4.12 ≈ 4
So, Option D one solution; c ≈ 4; B = 30°; C = 31° is correct.
4 because when rounded to the nearest tenths it will not increase the number as it is below 5
The answer is
G=105. I know this because look at the picture lol. You're welcome though.
