A 755 N diver drops from a board 10.0 m above the water's surface. Find the

What 2 characteristics of stars are shown in an H-R diagram?

Vinil7 [7]

<span>2 characteristics of stars are shown in an H-R diagram is S</span>ize and Color.

5 0

3 years ago

Two gerbils run in place with a linear speed of 0.50 m/s on an exercise wheel that is shaped like a hoop. Find the angular momen

Brilliant_brown [7]

Answer:

$L = 0.018 kg m^2/s$

Explanation:

Angular speed and linear speed is related to each other as

$v = R\omega$

here we know that

$v = 0.50 m/s$

$R = 0.08 m$

now we have

$\omega = \frac{v}{R}$

$\omega = \frac{0.50}{0.08}$

$\omega = 6.25 rad/s$

Now we know that moment of inertia of the system is given as

$I = (2M + m)R^2 [tex][tex]I = (2\times 0.22 + 0.0045)(0.08)^2$

$I = 2.84 \times 10^{-3} kg m^2$

Now angular momentum of the system is given as

$L = I\omega$

$L = (2.84 \times 10^{-3})(6.25)$

$L = 0.018 kg m^2/s$

7 0

3 years ago

Two objects of the same mass are on two different planets. Planet A has a force of gravity that is stronger than that of Planet

Molodets [167]

Planet A’s Object will have a higher weight than planet B’s Object.

Explanation: When a planet has a stronger gravitational pull, the same object will weigh more despite having the same mass, because weight is simply how much gravity is pushing/pulling on something.

7 0

3 years ago

Read 2 more answers

A uniform beam XY is 100 cm long and weighs 4.0N.The beam rests on a pivot 60 cm from end X. A load of 8.0 N hangs from the beam

Alex777 [14]

Answer:

<h2>The magnitude of force F is 18N</h2>

Explanation:

The magnitude of the force in the set up can be solved for using the principle of moment. According to the principle, the sum of clockwise moment is equal to the sum of anticlockwise moments.

Moment = Force * perpendicular distance

Clockwise moments;

The force that acts clockwise is the unknown Force F and 4N force. If the beam rests on a pivot 60 cm from end X and a Force F acts on the beam 80 cm from end X, the perpendicular distance of the force F from the pivot is 80-60 = 20cm and the perpendicular distance of the 4N force from the pivot is 60-50 = 10cm

Moment of force F about the pivot = F * 20

Moment of 4N force about the pivot = 4*10 = 40Nm

Sum of clockwise moment = 40+20F...(1)

Anticlockwise moment;

The 8N will act anticlockwisely about the pivot.

The distance between the 8N force and the pivot is 60-10 = 50cm

Moment of the 8N force = 8*50

=400Nm...(1)

Equating 1 and 2 we have;

40+20F = 400

20F = 400-40

20F = 360

F = 18N

The magnitude of force F is 18N

6 0

4 years ago

Calculate area moment of inertia for a circular cross-section with 3 mm diameter:

Keith_Richards [23]

Answer:

Option D: 4 mm⁴

Explanation:

Formula for area moment of inertia for a circular cross-section is;

I = πd⁴/64

We are given diameter;

d = 3 mm

Thus;

I = π × 3⁴/64

I = 3.98 mm⁴

Approximating to a whole number gives;

I = 4 mm⁴

5 0

3 years ago