A cannon ball fired horizontally from a cliff has a velocity directed at 60 degrees above horizontal when it hits the ground 3.0 seconds later. how high is the cliff
2 answers:
Answer: 44.1 m
Explanation:
The canon ball is fired horizontally. Hence, the initial velocity in vertical direction, u=0.
It takes 3.0 s for the ball to hit the ground. t=3.0 s
the ball would experience acceleration due to gravity i.e. a=g=9.8 m/s²
The vertical distance covered = height of the cliff.
Using the equation of motion,
<u>Hence, the height of the cliff is 44.1 m. </u>
Since the ball is fired horizontally, the initial y velocity is zero and the time to hit the ground is the same as if the ball was simply dropped from the cliff. So you can solve the y position function:
giving a height of 44.1m.
The given final velocity vector tells us that the initial x-directed velocity was about 17m/s.
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Detailed solution of the question is given in the attached files.