A ball is thrown vertically upward with an initial velocity of 29.4 m/s². What is the maximum height reached by the ball? How lo
1 answer:
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Answer:
0.45 miles
Explanation:
since, car will be running on the edge of track, distance covered in one lap by car will be equal to circumference of track.\
we will use value of pi as 22/7
Circumference for any circular shape is given by
Hence, in one lap distance will be covered
in 7 laps distance will be covered.
but is given that 7 laps should be equal to 10 miles
so 10 miles will be equal to
Thus, diameter of track will be 0.45 miles to meet the requirement.
Hence the expression of ω in terms of m and k is
Given the expressions;
Equating both expressions we will have;
Divide both equations by 2π
Square both sides
Take the square root of both sides
Hence the expression of ω in terms of m and k is