Which number line represents the solution to the inequality

Aneli [31]

700/200=7/2 because devide by 100 and then=3 1/2 and half is .5 so= 3.5

8 0

3 years ago

Able, Ben and Cal each played a game able’s score was six times ben’s score, Cale score was a hird time of Able’s score write do

Feliz [49]

Answer:

6:1:2

Step-by-step explanation:

Let a = Able's score, b = Ben's score, and c = Cal's score.

Since

Able's score was 6 times Ben's score, that means a = 6b.

Cal's score was a third of Able's score, so that means c = a/3. And since a = 6b, that means c = 6b / 3 = 2b.

Thus, the ratio of Able's score to Ben's score to Cal's score, a:b:c, is 6:1:2, because c is twice as much as b and a is 6 times as much as b.

3 0

3 years ago

How to find domain and range on a graph

mamaluj [8]

Answer:

Please Find the answer below

Step-by-step explanation:

Domain : It these to values of x , for which we have some value of y on the graph. Hence in order to determine the Domain from the graph, we have to determine , if there is any value / values for which we do not have any y coordinate. If there are some, then we delete them from the set of Real numbers and that would be our Domain.

Range : It these to values of y , which are as mapped to some value of x in the graph. Hence in order to determine the Range from the graph, we have to determine , if there is any value / values on y axis for which we do not have any x coordinate mapped to it. If there are some, then we delete them from the set of Real numbers and that would be our Range .

4 0

3 years ago

The model represents an equation. What value of x makes the equation true?

ch4aika [34]

Let's build the equation counting how many x's and 1's are there on each side.

On the left hand side we have 5x's and 8 1's, for a total of $5x+8$

On the left hand side we have 3x's and 10 1's, for a total of $3x+10$

So, the equation we want to solve is

$5x+8 = 3x+10$

Subtract 3x from both sides:

$2x+8 = 10$

Subtract 8 from both sides:

$2x=2$

Divide both sides by 2:

$x=1$

8 0

3 years ago

Simplify this please

Ugo [173]

Answer:

$\frac{12q^{\frac{7}{3}}}{p^{3}}$

Step-by-step explanation:

Here are some rules you need to simplify this expression:

Distribute exponents: When you raise an exponent to another exponent, you multiply the exponents together. This includes exponents that are fractions. $(a^{x})^{n} = a^{xn}$

Negative exponent rule: When an exponent is negative, you can make it positive by making the base a fraction. When the number is apart of a bigger fraction, you can move it to the other side (top/bottom). $a^{-x} = \frac{1}{a^{x}}$ , and to help with this question: $\frac{a^{-x}b}{1} = \frac{b}{a^{x}}$ .

Multiplying exponents with same base: When exponential numbers have the same base, you can combine them by adding their exponents together. $(a^{x})(a^{y}) = a^{x+y}$

Dividing exponents with same base: When exponential numbers have the same base, you can combine them by subtracting the exponents. $\frac{a^{x}}{a^{y}} = a^{x-y}$

Fractional exponents as a radical: When a number has an exponent that is a fraction, the numerator can remain the exponent, and the denominator becomes the index (example, index here ∛ is 3). $a^{\frac{m}{n}} = \sqrt[n]{a^{m}} = (\sqrt[n]{a})^{m}$

$\frac{(8p^{-6} q^{3})^{2/3}}{(27p^{3}q)^{-1/3}}$ Distribute exponent

$=\frac{8^{(2/3)}p^{(-6*2/3)}q^{(3*2/3)}}{27^{(-1/3)}p^{(3*-1/3)}q^{(-1/3)}}$ Simplify each exponent by multiplying

$=\frac{8^{(2/3)}p^{(-4)}q^{(2)}}{27^{(-1/3)}p^{(-1)}q^{(-1/3)}}$ Negative exponent rule

$=\frac{8^{(2/3)}q^{(2)}27^{(1/3)}p^{(1)}q^{(1/3)}}{p^{(4)}}$ Combine the like terms in the numerator with the base "q"

$=\frac{8^{(2/3)}27^{(1/3)}p^{(1)}q^{(2)}q^{(1/3)}}{p^{(4)}}$ Rearranged for you to see the like terms

$=\frac{8^{(2/3)}27^{(1/3)}p^{(1)}q^{(2)+(1/3)}}{p^{(4)}}$ Multiplying exponents with same base

$=\frac{8^{(2/3)}27^{(1/3)}p^{(1)}q^{(7/3)}}{p^{(4)}}$ 2 + 1/3 = 7/3

$=\frac{\sqrt[3]{8^{2}}\sqrt[3]{27}p\sqrt[3]{q^{7}}}{p^{4}}$ Fractional exponents as radical form

$=\frac{(\sqrt[3]{64})(3)(p)(q^{\frac{7}{3}})}{p^{4}}$ Simplified cubes. Wrote brackets to lessen confusion. Notice the radical of a variable can't be simplified.