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devlian [24]
2 years ago
6

QUESTION 2.

Mathematics
1 answer:
masha68 [24]2 years ago
7 0

Answer:

c

Step-by-step explanation:

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May I please get help with this question?
Julli [10]
The answer should be 42 times.
5 0
3 years ago
Read 2 more answers
The ages of three siblings are consecutive integers. The sum of their ages is 42. Calculate their ages. *
stealth61 [152]

Answer:

13, 14, 15

Step-by-step explanation:

Let x = age of one of the siblings

Since the age of the siblings are consecutive integers, the age of the next sibling would be x + 1 and the age of the third sibling would be x + 2

x +( x +1) + (x +2) = 42

3x + 3 = 42

collect like terms and solve for x

x = 13

The age of the first sibling is 13

The age of the second sibling is x + 1 = 13 + 1 = 14

The age of the third sibling is x + 2 = 13 + 2 = 15

8 0
2 years ago
Convert 89/10 into a mixed number ​
kompoz [17]

Answer:

8 9/10

Step-by-step explanation:

89 goes into 10 8 times.

8x10=80.

89-80=9

So the answer is 8 9/10

6 0
2 years ago
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Solve the system using substitution.
valkas [14]

Good evening ,

Answer:

<h2>(3,15)</h2>

Step-by-step explanation:

y=5x then

4x-y= -3 ⇌ 4x-5x= -3 ⇌ -x= -3 ⇌ x=3

and since y=5x then y=5×3=15.

______________________________

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5 0
2 years ago
The sum of four consecutive integers is 342. What is the third term in the sequence
Fofino [41]

Answer:

86

Step-by-step explanation:

let  four consecutive integers: n  , n+1  , n+2  , n+3

n  + n+1  + n+2 + n+3 = 342

4n + 6 = 342

4n + 6  - 6  = 342 - 6

4n = 336

divid by : 4

n = 84

but the third term is : n +2   so : 84+2 = 86

4 0
3 years ago
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