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madam [21]
3 years ago
14

(Worth 50 points )Evaluate the expression when g = 0.6. 400g^2−0.9÷g Enter your answer as a decimal in the box.

Mathematics
2 answers:
Goshia [24]3 years ago
7 0

Answer:

142.5

Step-by-step explanation:

g = 0.6

First plug in the value of g, which is 0.6, into the problem⤵⤵⤵

400(0.6)^2 - 0.9 ÷ (0.6)

Remember PEMDAS

First off 0.6^2 is the same as 0.6 × 0.6 which is 0.36 .

Next multiply 400 and 0.36 to get 144 .

Then divide 0.9 by 0.6 to get 1.5 .

Lastly subtract 1.5 from 144 to get 142.5 .

This took me a while, because I was confusing myself a little, but I finally got it done. Here you go, hope this helps :)

Firdavs [7]3 years ago
7 0

Answer:

142.5

Step-by-step explanation: In Evaluate Expressions There Could Be Decimal In These But Also A Normal Number

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How to find value of y in polygon JKLM
Yuki888 [10]

Answer:

y = 22.5


Step-by-step explanation:

Here, the 4 angles shown are all exterior angles of the polygon.

The sum of the exterior angles of a polygon is ALWAYS 360°


<em>So we add up the 4 angles (given in terms of y) and sum it to 360 and solve for y:</em>

4y+2y+6y+4y=360\\16y=360\\y=\frac{360}{16}=22.5


y = 22.5


4 0
4 years ago
Find the value of x in the figure. A. 6 C. 3 B. 5 D. 7
WITCHER [35]
You didn’t provide a picture
4 0
4 years ago
Read 2 more answers
Which answer is true
Veseljchak [2.6K]

\star=x\\\triangle=1\\\\\text{the equation:}\\\\5\star=5\triangle\\\\therefore\\\\5x=5\cdot1\\\\\boxed{5x=5}



Answer: D. 5x = 5

8 0
3 years ago
How do you find the middle term of a perfect square trinomial?
Lyrx [107]

Answer:

Take the square root of the constant (number w/o the variable) and then multiply that by 2.

Step-by-step explanation:

A perfect square trinomial is something like this: x^{2} +6x+9. If I have 6x, and I want to find the last term I would take half a six and then square it to get 9.

SO.... To get the middle term of a perfect square trinomial, you would need to do the reverse.. So...

1) Take the square root of the constant...

2) Multiply that by 2

4 0
4 years ago
Evaluate................
wolverine [178]

Answer:

h(8q²-2q) = 56q² -10q

k(2q²+3q) = 16q² +31q

Step-by-step explanation:

1. Replace x in the function definition with the function's argument, then simplify.

h(x) = 7x +4q

h(8q² -2q) = 7(8q² -2q) +4q = 56q² -14q +4q = 56q² -10q

__

2. Same as the first problem.

k(x) = 8x +7q

k(2q² +3q) = 8(2q² +3q) +7q = 16q² +24q +7q = 16q² +31q

_____

Comment on the problem

In each case, the function definition says the function is not a function of q; it is only a function of x. It is h(x), not h(x, q). Thus the "q" in the function definition should be considered to be a literal not to be affected by any value x may have. It could be considered another way to write z, for example. In that case, the function would evaluate to ...

h(8q² -2q) = 56q² -14q +4z

and replacing q with some value (say, 2) would give 196+4z, a value that still has z as a separate entity.

In short, I believe the offered answers are misleading with respect to how you would treat function definitions in the real world.

7 0
4 years ago
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