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Liula [17]
3 years ago
9

How do you find the middle term of a perfect square trinomial?

Mathematics
1 answer:
Lyrx [107]3 years ago
4 0

Answer:

Take the square root of the constant (number w/o the variable) and then multiply that by 2.

Step-by-step explanation:

A perfect square trinomial is something like this: x^{2} +6x+9. If I have 6x, and I want to find the last term I would take half a six and then square it to get 9.

SO.... To get the middle term of a perfect square trinomial, you would need to do the reverse.. So...

1) Take the square root of the constant...

2) Multiply that by 2

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HELP!
igomit [66]

Answer:

2

Step-by-step explanation:

6 0
3 years ago
Hi. I need help. This is for homework I would appreciate it if you helped.
Triss [41]

Answer:

Ik this isn't an answer but wanted to say good luck im battling stuff too :(

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
5) In a certain supermarket, a sample of 60 customers who used a self-service checkout lane averaged 5.2 minutes of checkout tim
Ne4ueva [31]

Answer:

\S^2_p =\frac{(60-1)(3.1)^2 +(72 -1)(2.8)^2}{60 +72 -2}=8.643

S_p=2.940

t=\frac{(5.2 -6.1)-(0)}{2.940\sqrt{\frac{1}{60}+\frac{1}{72}}}=-1.751

df=60+72-2=130

p_v =P(t_{130}

Assuming a significance level of \alpha=0.05 we have that the p value is lower than this significance level so then we can conclude that the mean for checkout time is significantly less for people who use the self-service lane

Step-by-step explanation:

Data given

Our notation on this case :

n_1 =60 represent the sample size for people who used a self service

n_2 =72 represent the sample size for people who used a cashier

\bar X_1 =5.2 represent the sample mean for people who used a self service

\bar X_2 =6.1 represent the sample mean people who used a cashier

s_1=3.1 represent the sample standard deviation for people who used a self service

s_2=2.8 represent the sample standard deviation for people who used a cashier

Assumptions

When we have two independent samples from two normal distributions with equal variances we are assuming that  

\sigma^2_1 =\sigma^2_2 =\sigma^2

The statistic is given by:

t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{S_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}}}

And t follows a t distribution with n_1+n_2 -2 degrees of freedom and the pooled variance S^2_p is given by this formula:

\S^2_p =\frac{(n_1-1)S^2_1 +(n_2 -1)S^2_2}{n_1 +n_2 -2}

System of hypothesis

Null hypothesis: \mu_1 \geq \mu_2

Alternative hypothesis: \mu_1 < \mu_2

This system is equivalent to:

Null hypothesis: \mu_1 - \mu_2 \geq 0

Alternative hypothesis: \mu_1 -\mu_2 < 0

We can find the pooled variance:

\S^2_p =\frac{(60-1)(3.1)^2 +(72 -1)(2.8)^2}{60 +72 -2}=8.643

And the deviation would be just the square root of the variance:

S_p=2.940

The statistic is given by:

t=\frac{(5.2 -6.1)-(0)}{2.940\sqrt{\frac{1}{60}+\frac{1}{72}}}=-1.751

The degrees of freedom are given by:

df=60+72-2=130

And now we can calculate the p value with:

p_v =P(t_{130}

Assuming a significance level of \alpha=0.05 we have that the p value is lower than this significance level so then we can conclude that the mean for checkout time is significantly less for people who use the self-service lane

5 0
3 years ago
Please help
bazaltina [42]

Answer:

6

Step-by-step explanation:

8(1/2) + 2(4)

/2

4 + 8

/2

12/2

6

6 0
3 years ago
Read 2 more answers
so a group of students are in a club. half are boys ,4/9 of the boys have brown eyes. how many boys have brown eyes?
aliina [53]
it will have to be 5/9 or0.5555555556
8 0
3 years ago
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