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3 years ago

2x2-5x-2 solve by quadratic formula 9leave answers in simplest radical form)

Mathematics

1 answer:

Talja [164]3 years ago

6 0

Answer:

-5x+2

Step-by-step explanation:

1. Multiply number 2 and 2=4 so it is

4-5x-2

2. Combine like terms

-5x+4-2

3. Subtract the numbers

-5x+2

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93.9x10`2)+(2.3x10`6)=

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(93.9x100) + (2.3x1,000,000)
9,390 + 2,300,000
2,309,390

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3 years ago

A study showed that 14 of 180 publicly traded business services companies failed a test for compliance with Sarbanes-Oxley requi

Vika [28.1K]

Answer:

The 95% confidence interval for the overall noncompliance proportion is (0.0387, 0.1169).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

For this problem, we have that:

$n = 180, \pi = \frac{14}{180} = 0.0778$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.0778 - 1.96\sqrt{\frac{0.0778*0.9222}{180}} = 0.0387$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.0778 + 1.96\sqrt{\frac{0.0778*0.9222}{180}} = 0.1169$

The 95% confidence interval for the overall noncompliance proportion is (0.0387, 0.1169).

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3 years ago

Order the numbers from least to greatest

Ghella [55]

-2 3/4, -2.7, -1.7, -1, -3/5, -0.5, 0.2, 1 3/4

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3 years ago

Sixty percent of the eligible voting residents of a certain community support the incumbent candidate. If eight of the residents

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By the binomial theorem we know that

$1 = (.4 + .6)^8 \\ = {8 \choose 0} (.4)^{8} (.6)^{0} + {8 \choose 1} (.4)^{7} (.6)^{1} +{8 \choose 2} (.4)^{6} (.6)^{2} + {8 \choose 3} (.4)^{5} (.6)^{3} + {8 \choose 4} (.4)^{4} (.6)^{4} \\ + \quad {8 \choose 5} (.4)^{3} (.6)^{5} + {8 \choose 6} (.4)^{2} (.6)^{6} + {8 \choose 7} (.4)^{1} (.6)^{7} + {8 \choose 8} (.4)^{0} (.6)^{8}$