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serg [7]
3 years ago
6

Cost of a pen: $0.95 Markup: 60%

Mathematics
1 answer:
julia-pushkina [17]3 years ago
5 0
Multiply the $0.95 by .06 or if you have a percentage button then do $0.95 by 60% and you’ll get your answer of 0.57
You might be interested in
What force would be required to accelerate a 1,100 kg car to 0.5m/s?
ira [324]

Answer:

550 N

Step-by-step explanation:

We can solve the problem by using Newton's second law:

F=ma

F is the force required to accelerate the car

m is the mass of the car

a is the acceleration of the car

In this problem, the mass is m=1100 kg, while the acceleration is a=0.5 m/s^2, therefore the force required to accelerate the car is

F=ma=(1100kg)(0.5m/s^{2} )=550N

Hope this helps!

3 0
3 years ago
A car travels about 25 miles on 1 gallon of gas. About how far can the car travel on 8 gallons of gas?
Arada [10]
The answer is
8x25 = 200 miles
4 0
3 years ago
At an archeological site, the remains of two ancient step pyramids are congruent. If ABCD= EFGH find EF
Pani-rosa [81]

Answer:

EF = 44 ft

Step-by-step explanation:

Given that ABCD is congruent to EFGH, it follows that their corresponding lengths and angles would be congruent to each other.

This means, for the sides:

AB = EF,

BC = FG,

CD = GH

AD = EH.

Therefore, if AB = 44 ft, corresponding side, EF = 44 ft

4 0
2 years ago
Read 2 more answers
Lindsay and menonhave 1,240 stickers.menon has 4 times as many stickers as Lindsay.menon decides to have 6 stickers on each page
Lemur [1.5K]

a) Menon has 992 stickers. We can find this by writing an algebraic expression for the number of stickers, with x being the number that Lindsay has. This gives us:

x + 4x = 1240

5x = 1240

x = 248

Now we multiply 248 by 4 to get 992.

b) There are 2 stickers left over. First we have to divide 992 by 6, which gives us 165 as a whole number, but then a remainder of 2. That means that there are two stickers left.

c) Menon needs 4 more stickers, as 6 - 2 = 4, and there are 6 stickers per page.

I hope this helps! Let me know if you have any questions :)


5 0
3 years ago
Common factor 32? composite or prime will both work
Fed [463]
Usually when asking for common factors they ask you to compare two or more different numbers but the factors of 32 are:

1, 2, 4, 8, 16, 32
5 0
3 years ago
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