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OverLord2011 [107]
3 years ago
14

A scientist weighs a sample of iron on Scale 1 and weighs a sample of mercury on

Mathematics
1 answer:
katrin [286]3 years ago
4 0

Answer:

dont waste yo time pls sorryy:/

ur mom is hot <3

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What is m∠1? help me please
Natalija [7]

Answer:

m∠1=111°

Step-by-step explanation:

Since angle 1 is an exterior angle on a straight line, it is the sum of the two outer angles of the triangle.

64+47=111.

8 0
3 years ago
Read 2 more answers
5u-2u=..................................................
MAVERICK [17]
It will be 3u good luck
8 0
3 years ago
What is the domain and range and function ??? Then can u explain how u did it please and thank you
enot [183]
The domain is
- 10 \leqslant x \leqslant 10
and the range is
- 5 \leqslant y \leqslant 5
Domain is x values (horizontal axis), while range is y values (vertical axis). On a line like this one, domain is calculated from the left most point to the right most, while range is calculated from the down most to the upmost.
Because this line is a solid line rather than a dotted line, less than or equal to
\leqslant
signs are used rather than just
<
less than signs.


6 0
3 years ago
Line ℓ1 has the equation
aleksley [76]

Answer:

\sqrt{2} units

Step-by-step explanation:

The Line 1 has equation x + y = 5 ....... (1) , and  

Line 2 has equation x + y = 3 .......... (2)

Now, we have to find the perpendicular distance between line 1 and line 2.

We can say that (3,0) is a point on line 2 as it satisfies the equation (2).

Now, the perpendicular distance from point (3,0) to the line 1 will be given by the formula

\frac{|3 + 0 - 5|}{\sqrt{1^{2}+ 1^{2}}} = \frac{2}{\sqrt{2}} = \sqrt{2} units (Answer)

We know that the perpendicular distance from any external point (x_{1},y_{1}) to a given straight line ax + by + c = 0 is given by the formula \frac{|ax_{1} + by_{1} + c|}{\sqrt{a^{2} + b^{2}}}.

3 0
3 years ago
Sarah sold a total of 178 t shirts and posters at a festival. She sold 46 more tshirts than poster. How many posters did she sel
ycow [4]

Sarah sold 66 posters

<em><u>Solution:</u></em>

Let "a" be the number of shirts sold

Let "b" be the number of posters sold

<em><u>Sarah sold a total of 178 t shirts and posters at a festival</u></em>

Therefore,

number of shirts sold + number of posters sold = 178

a + b = 178 ----------- eqn 1

<em><u>She sold 46 more tshirts than poster</u></em>

Number of shirts sold = 46 + number of posters sold

a = 46 + b --------- eqn 2

<em><u>Substitute eqn 2 in eqn 1</u></em>

46 + b + b = 178

2b = 178 - 46

2b = 132

b = 66

Thus she sold 66 posters

7 0
3 years ago
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