Eight hundred and ninety-six point eight hundred and fifty-four.
D fed ifjk vs cjsioxhdjducjskvuhdkfuxhxiufuc
Answer:
y = 17(2)^x
Step-by-step explanation:
If the graph of y = ab^x goes through (0, 17), then
17 = ab*0, or a = 17
Then the function is y = ab^x with a = 17, or
y = 17*b^x and we must find b.
If the graph of y = 17*b^x also goes through (6, 1088), then the following must be true: 1088 = 17*b^6
which reduces to 64 = b^6
Taking the sixth root of both sides, we get 64^(1/6) = b, and so b = 2
Then the desired exponential function is
y = 17(2)^x
I’m not so sure but I think it’s a carrot
Answer:
900
Step-by-step explanation:
We assume that your 4-digit number must be in the range 1000 to 9999. Clearly, any number ending in zero will meet your requirement:
1000/100 = 10
3890/389 = 10
However, the requirement cannot be met when the 1s digit is other than zero.
__
For some 3-digit number N and some 1s digit x, the 4-digit number will be
4-digit number: 10N+x
Dividing this by N will give ...
(10N+x)/N = 10 remainder x
N will only be a factor of 10N+x when x=0.
So, there are 900 4-digit numbers that meet your requirement. They range from 1000 to 9990.
