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3 years ago

The thick loess deposits in South Dakota, Nebraska, and Iowa come from _____.

Biology

2 answers:

kozerog [31]3 years ago

6 0

The thick loess deposits in South Dakota, Nebraska, and Iowa come from Glacial Sediments.

The glaciers contain ice, snow, water, rocks and sediment and when the glacier moves, it pushes rocks and sediments which is called glacial sediment. The thick loess deposits in South Dakota, Nebraska, and Iowa come from same Glacial Sediments of the Last Glacial Period (of Ice Age).

bija089 [108]3 years ago

4 0

The thick loess deposits in South Dakota, Nebraska, and Iowa come from the glacial sediments from the last ice age glacial period.

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What does it mean for an organism to be anaerobic

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so that organism know as anaerobic
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What is a semi permuable membrane

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3 years ago

Si se aparean especies diferentes como por ejemplo el cruce entre caballos y burros; podemos afirmar que si llegan a tener desce

White raven [17]

Answer:

El híbrido va a ser esteril.

Explanation:

En la cruza entre dos especies distintas, cuando ocurre, existen distintos mecanismos de aislamiento reproductivo, que son barreras que inhiben o interrumpen el flujo génico entre especies distintas. Es decir que no habrá exito reproductivo de estas cruzas. Se trata de caracteres biológicos propios de cada especie que previenen la reproducción con otras especies.

Estos mecanismos de aislamiento reproductivo pueden ser precigóticos o postcigóticos.

1.Pre-copulatorios o pre-cigóticos:

Ecológico o por aislamiento de hábitat;

Estacional o temporal;

Sexual o etológico;

Mecánico;

Por incompatibilidad de gametas.

2. Post-copulatorios o cigóticos:

Inviabilidad del híbrido;

Esterilidad del híbrido;

Híbrido con viabilidad o fertilidad disminuido;

Interacciones citoplasmáticas.

La mula es producto de la cruza entre dos especies distintas: una yegua (Equus ferus caballus) y un burro (Equus africanus asinus). Es un ejemplo de la accion de mecanismo poscigótico, en el cual se forma un híbrido viable esteril. Este ejemplar puede nacer, crecer y sobrevivir, pero que no puede producir gametas funcionales, por lo cual no puede reproducirse.

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3 years ago

1. How does the body adjust to a higher altitude?

Anni [7]

During acclimatization over a few days to weeks, the body produces more red blood cells to counteract the lower oxygen saturation in blood in high altitudes. Full adaptation to high altitude is achieved when the increase of red blood cells reaches a plateau and stops.Heart rate is controlled by the two branches of the autonomic (involuntary) nervous system. The sympathetic nervous system (SNS) and the parasympathetic nervous system (PNS). ... At the beginning of exercise, your body removes the parasympathetic stimulation, which enables the heart rate to gradually increase.

D)all of them

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3 years ago

1. Flower position, stem length, and seed shape are three characters that Mendel studied. Each is controlled by an independently

maria [59]

Answer:

a. 1/64 AATTDD

b. 1/64 aattdd

c. 8/64=1/8 AaTtDd

d. 2/64 = 1/32 AATTDd or aattDd or AAttDd or aaTTDd

Explanation:

Available data:

Flower position: Axial (A) is dominant to Terminal (a)

Stem length: Tall (T) is dominant to dwarf (t)

Seed shape: Round (R) is dominant to wrinkled (r)

Cross:

Parental) AaTtDd x AaTtDd

Knowing that these four genes assort independently, then we can infer that the F1 will have the next genotypic proportions for each gene:

AA= 1/4

Aa =2/4

aa = 1/4

TT = 1/4

Tt = 2/4

tt = 1/4

DD = 1/4

Dd = 2/4

dd = 1/4

This is the same as developing a Punnett square for each gene separately.

Knowing this, to get each of the mentioned genotypes for each trait, we must multiply their respective genotypic proportions, like this:

a. homozygous for the three dominant traits, AATTDD

AA1/4 x TT 1/4 x DD 1/4 = AATTDD 1/64

b. homozygous for the three recessive traits, aattdd

aa 1/4 x tt 1/4 x dd 1/4 = aattdd 1/64

c. heterozygous for all three characters, AaTtDd

Aa 2/4 x Tt 2/4 x Dd 2/4 = AaTtDd 8/16=1/8

d. homozygous for axial and tall, heterozygous for seed shape. There are four possibilities, all of them with the same result:

AATTDd --> 1/4 x 1/4 x 2/4 = 2/64=1/32

aattDd ---> 1/4 x 1/4 x 2/4 = 2/64=1/32

AAttDd ---> 1/4 x 1/4 x 2/4 = 2/64=1/32

aaTTDd ---> 1/4 x 1/4 x 2/4 = 2/64=1/32

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3 years ago

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