Answer:
The correct option is d) head.
Explanation:
Bicoid protein works as a transcription factor. It enters the nuclei of the embryos in early segmentation, where it activates the hunchback gene. In Drosophila, embryonic development begins at the time of fertilization. The sperm enters the mature oocyte through the micropile, a structure located in what will be the anterior region of the egg. Bicoid and hunchback mRNAs, protein products are critical for the formation of the head and thorax. Already in the early stages of oocyte development, certain mRNAs are located in specific regions of the oocyte: mRNA molecules encoding the Bicoid protein are preferentially located in the anterior region of the oocyte. Moderate levels of the bicoid protein are necessary to activate the formation of the thorax (i.e., the expression of the hunchback gene) but the formation of the head requires high concentrations of Bicoid, the promoters of a specific gap gene of the head must have sites of low affinity binding for Bicoid, so that this gene can be activated only in extremely high concentrations of Bicoid.
The lack of Bicoid protein affects the formation of the head and other structures in the anterior region of the oocyte.
the force of bestop will fling you forward and the water will go to one side of the bottle and hit the side of the bottle and curved back up and come out because the force of
Answer:
50%
Explanation:
This question involves a single gene with two alleles W and w in puppies. According to the question, the genotype of the parent organisms are Ww. In a cross between the two parents i.e. Ww × Ww, the following gametes will be produced by each parent: W and w.
Using these gametes in a punnet square (see attached image), the following genotype of offsprings will be produced: WW, Ww, Ww, ww. Hence, based on this question, the percentage of puppies that would have the same genotype as the parents, Ww are 1/2 × 100% = 50%.
If the Na+ voltage-gated channels in a muscle cell open, the Na (sodium) ions rush inside the muscle cell and makes the cell more positive as Na ions carry positive charge on it. Due to the entry of positively charged ions inside the cell, the cell becomes less negative and more positive. This is called depolarization of cell.
