(i.) CA = πrl
CA = π (5*13)
CA = 65π
(ii.) TA = πrl + πr^2
TA = 65π + π (5^2)
TA = 65π + 25π
TA = 90π
(iii.) To get the height of the cone, you have to use the Pythagorean theorem. Plug in the radius for a and the slant height for c.
a^2 + b^2 = c^2
5^2 + b^2 = 13^2
25 + b^2 = 169 Height = 12
b^2 = 144
b = 12
(iv.) v = (1/3)πr^2h
v = (1/3)π(5^2)*12
v = (1/3)π(25*12)
v = (1/3)π*300
v = 100π
Answer: 4x² + 3x + 52
Step-by-step explanation:
1. rearrange & simplify terms:
(4x² - 4 + 6) + (3x - 7² + 1) . . .
(4x² + 2) + (3x + 49 + 1) . . .
(4x²+2) + (3x + 50).
2. combine like terms in standard form:
<u>4x² + 3x + 52</u>
Answer:
x=2
Step-by-step explanation:
5x+
= 7
5x+4 =7 (2)
5x+4=14
5x=14-4
5x=10
= 
x=2
Answer:
13.20 teaspoon of fertiliser needed for entire garden.
Step-by-step explanation:
Diameter of the garden = 14.50 ft
Radius of the garden = 7.25 ft
Area
[tex]A=\pi r^2[/text]
[tex]A=\pi \times 7.25 \times 7.25[/text]
[tex]\pi=3.14[/text]
[tex]A=\pi \times 7.25 \times 7.25[/text]
[tex]A=3.14 \times 7.25 \times 7.25[/text]
Hence
[tex]A=165.046[/text]
Area is 165.046 Sq Ft
For 25 sq ft of fields the fertiliser needed = 2 tea spoon
For 1 sq ft of fields the fertiliser needed =
[tex]\frac{2}{25}[/text] tea spoon
For 165.046 sq ft of fields the fertiliser needed =
[tex]\frac{2 \times 165.046 }{25}[/text] tea spoon
For 165.046 sq ft of fields the fertiliser needed = 13.20 tea spoon
