Answer:
C and B.
Step-by-step explanation:
f(x) = 4 - x^2.
The degree of f(x) is 2, which means it is a quadratic graph. The coefficient of x^2 is negative, which means the curve is pointing downwards. The only curve that satisfies this is Graph C.
f(x) = 2^x + 5.
Notice that 2^x is positive for all real values of x. Therefore the answer is Graph B.
Answer:
A) x ≠ 0
B) x ≠ 3
Step-by-step explanation:
The domain is all the possible values of x such that f(x) exists.
A) f(x) = (x + 5) / x
x can't be 0 (can't divide by 0), so the domain of x is all values other than 0.
You can write this in interval notation:
(-∞, 0)⋃(0, ∞)
Inequality notation:
x < 0 or x > 0
Or simply:
x ≠ 0
B) f(x) = 1 / (x - 3)
x can't be 3 (can't divide by 0), so the domain of x is all values other than 3.
(-∞, 3)⋃(3, ∞)
x < 3 or x > 3
x ≠ 3
One number is x
other number is 3x-10
x + 3x - 10 = 50
4x = 50 + 10
4x = 60
x = 60/4
x = 15 ← one number
the other number = 3x - 10 = 3*15 - 10 = 35
