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3 years ago

HELP PLEASE, I will mark brainless

Mathematics

1 answer:

ahrayia [7]3 years ago

4 0

To find the slope take two ordered pairs and put them in form of x2-x1/y2-y1 and then you can find the slope.

(-2,17) (-3,20)

(-2)-(-3) = 1
(17)-(20)=-3

slope is 1/-3

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What is the equation of this line?

hram777 [196]

Y=1/2x

If that helps please make sure to mark as brainliest!
-procklown

7 0

4 years ago

Shelia went snowboarding. She spent $118 for the pass and snowboard rental. The snowboard rental cost $25. What percent of the t

Gnesinka [82]

Answer:

82.52%

Step-by-step explanation:

118+25=143

$\frac{118}{143} =\frac{x}{100}$

solve for x

$(118*100)/143= 82.5175$

4 0

3 years ago

Use the distance formula to determine the distance between (-8,10) and (-6,7)

hjlf

Answer:

Distance: $\sqrt{13}$ units

Step-by-step explanation:

The distance formula is $d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$ where:

$d$ is the distance between points $(x_1,y_1)$ and $(x_2,y_2)$
$(x_1,y_1)$ are the coordinates of the first point
$(x_2,y_2)$ are the coordinates of the second point

We are given that:

$(x_1,y_1)=(-8,10)$
$(x_2,y_2)=(-6,7)$

To determine the value of our distance, $d$ , we plug in our given information into the formula and solve for

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

$d=\sqrt{(-6-(-8))^2+(7-10)^2}$

$d=\sqrt{(-6+8)^2+(-3)^2}$

$d=\sqrt{(2)^2+(-3)^2}$

$d=\sqrt{4+9}$

$d=\sqrt{13}$

Therefore, the distance between $(-8,10)$ and $(-6,7)$ is $\sqrt{13}$ units.

See the attached graph for a visual.

5 0

3 years ago

The graph for the system of inequalities without the shading of its solution set is shown on the coordinate grid.

BartSMP [9]

Answer:

C. Area 3

Step-by-step explanation:

<h3>The first line</h3>

Line x - y > 5 ⇒ y < x - 5

<u>This line has positive slope and the y-intercept is -5, shaded area is below the line, covers the areas:</u>

Area 3 and Area 4

<h3>The second line</h3>

Line x + 2y < -6 ⇒ 2y < - x - 6 ⇒ y < -1/2x - 3

<u>This line has negative slope and the y-intercept is -3, shaded are is below the line, covers the areas:</u>

Area 2 and Area 3

<u>Solution of the system is the intersection of the areas:</u>

Area 3

5 0

3 years ago

Mrs. Hall records the heights of 50 students in a spreadsheet. The mean height is 68 inches. After looking at the data again, sh

Vedmedyk [2.9K]

67.3 repeating. You multiply 68 times 50, subtract 82 and 86, them divide by 48. If that doesn't work, try dividing by 50. That should work.

8 0

3 years ago

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