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2 years ago

20.00 20.00 x 1.00 0.00 Function or Not a Function Circle One

Mathematics

1 answer:

ololo11 [35]2 years ago

3 0

Answer:

The function would be 20.00

Step-by-step explanation:

I think...I dont really know if any of those numbers are functions cause I always have ordered pairs as functions but whatever lol

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What is the answer for number 6?

telo118 [61]

They will each get 1/6th pound of raspberries

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3 years ago

Read 2 more answers

NO LINKS!!! What is the equation of these two graphs?

S_A_V [24]

Answer:

$\textsf{1.} \quad y=-\dfrac{1}{30}x^2+\dfrac{1}{2}x+\dfrac{68}{15}\:\:\textsf{ where}\:\:x \geq \dfrac{15-\sqrt{769}}{2}\\\\\quad \textsf{or} \quad y=2\sqrt{x+5}$

$\textsf{2.} \quad y=-|x+1|+5$

Step-by-step explanation:

<h3>Question 1</h3>

Method 1 - modelling as a quadratic with restricted domain

Assuming that the points given on the graph are points that the curve passes through, the curve can be modeled as a quadratic with a limited domain. Please note that as the x-intercept has not been defined on the graph, I am not including this in this first method.

Standard form of a quadratic equation:

$y=ax^2+bx+c$

Given points:

(-4, 2)
(-1, 4)
(4, 6)

Substitute the given points into the equation to create 3 equations:

Equation 1 (-4, 2)

$\implies a(-4)^2+b(-4)+c=2$

$\implies 16a-4b+c=2$

Equation 2 (-1, 4)

$\implies a(-1)^2+b(-1)+c=4$

$\implies a-b+c=4$

Equation 3 (4, 6)

$\implies a(4)^2+b(4)+c=6$

$\implies 16a+4b+c=6$

Subtract Equation 1 from Equation 3 to eliminate variables a and c:

$\implies (16a+4b+c)-(16a-4b+c)=6-2$

$\implies 8b=4$

$\implies b=\dfrac{4}{8}$

$\implies b=\dfrac{1}{2}$

Subtract Equation 2 from Equation 3 to eliminate variable c:

$\implies (16a+4b+c)-(a-b+c)=6-4$

$\implies 15a+5b=2$

$\implies 15a=2-5b$

$\implies a=\dfrac{2-5b}{15}$

Substitute found value of b into the expression for a and solve for a:

$\implies a=\dfrac{2-5(\frac{1}{2})}{15}$

$\implies a=-\dfrac{1}{30}$

Substitute found values of a and b into Equation 2 and solve for c:

$\implies a-b+c=4$

$\implies -\dfrac{1}{30}-\dfrac{1}{2}+c=4$

$\implies c=\dfrac{68}{15}$

Therefore, the equation of the graph is:

$y=-\dfrac{1}{30}x^2+\dfrac{1}{2}x+\dfrac{68}{15}$

$\textsf{with the restricted domain}: \quad x \geq \dfrac{15-\sqrt{769}}{2}$

Method 2 - modelling as a square root function

Assuming that the points given on the graph are points that the curve passes through, and the x-intercept should be included, we can model this curve as a square root function.

Given points:

(-4, 2)
(-1, 4)
(4, 6)
(0, -5)

The parent function is:

$y=\sqrt{x}$

Translated 5 units left so that the x-intercept is (0, -5):

$\implies y=\sqrt{x+5}$

The curve is stretched vertically, so:

$\implies y=a\sqrt{x+5} \quad \textsf{(where a is some constant)}$

To find a, substitute the coordinates of the given points:

$\implies a\sqrt{-4+5}=2$

$\implies a=2$

$\implies a\sqrt{-1+5}=4$

$\implies 2a=4$

$\implies a=2$

$\implies a\sqrt{4+5}=6$

$\implies 3a=6$

$\implies a=2$

As the value of a is the same for all points, the equation of the line is:

$y=2\sqrt{x+5}$

<h3>Question 2</h3>

Vertex form of an absolute value function

$f(x)=a|x-h|+k$

where:

(h, k) is the vertex
a is some constant

From inspection of the given graph:

vertex = (-1, 5)
point on graph = (0, 4)

Substitute the given values into the function and solve for a:

$\implies a|0-(-1)|+5=4$

$\implies a+5=4$

$\implies a=-1$

Substituting the given vertex and the found value of a into the function, the equation of the graph is:

$y=-|x+1|+5$

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1 year ago

12x(8x-20)÷4(2x-5) please solve it

Basile [38]

Answer: 48 $x^{3}$ -240 $x^{2}$ +300x

hopes this helps

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2 years ago

a student phototcopies a drawing without realizing tht the copier is set to enlarge the image by 15%. if the height of the actua

Nataly_w [17]

If an image is being enlarged by 15% you would take the base number multiply it by the percent in decimal form and add the result to the base number.

4.25*0.15=0.6275

0.6375+4.25=4.8875

Answer: 4.8875

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3 years ago

Help pleaseee one of them is positive fractions and procedural fluency

navik [9.2K]

5) make the 5 a fraction (5/1) then use keep change flip to make the equation 5/1 * 10/3

That will give you 50/3, simplify that and you get 16 2/3

16 2/3 is your final answer

6) use keep change flip to make the equation 8/10 * 5/2

This will give you 40/20

Since 40 goes into twenty the answer is 2

2 is your final answer

3 0

1 year ago