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kotykmax [81]
3 years ago
10

Can you please show me how to do:

Mathematics
2 answers:
Anettt [7]3 years ago
6 0
6sqr(3)×sqr(3)/3
[6sqr(3)×sqr(3)]/3
sqr(3)×sqr(3)=sqr(3)^2=3
(6×3)/3
3's cancel
6 is the answer
USPshnik [31]3 years ago
3 0

Step-by-step explanation:

6\sqrt3\cdot\dfrac{\sqrt3}{3}=\dfrac{(6\sqrt3)(\sqrt3)}{3}\\\\\text{use the associative property}\ (a\times b)\times c=a\times(b\times c)\\\\=\dfrac{(6)(\sqrt3\cdot\sqrt3)}{3}\\\\\text{use}\ \sqrt{a}\cdot\sqrt{a}=a\\\\=\dfrac{(6)(\not3)}{\not3}\qquad\text{cancel 3}\\\\=6

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andre [41]

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