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kotykmax [81]
4 years ago
10

Can you please show me how to do:

Mathematics
2 answers:
Anettt [7]4 years ago
6 0
6sqr(3)×sqr(3)/3
[6sqr(3)×sqr(3)]/3
sqr(3)×sqr(3)=sqr(3)^2=3
(6×3)/3
3's cancel
6 is the answer
USPshnik [31]4 years ago
3 0

Step-by-step explanation:

6\sqrt3\cdot\dfrac{\sqrt3}{3}=\dfrac{(6\sqrt3)(\sqrt3)}{3}\\\\\text{use the associative property}\ (a\times b)\times c=a\times(b\times c)\\\\=\dfrac{(6)(\sqrt3\cdot\sqrt3)}{3}\\\\\text{use}\ \sqrt{a}\cdot\sqrt{a}=a\\\\=\dfrac{(6)(\not3)}{\not3}\qquad\text{cancel 3}\\\\=6

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Is this the right answer?
zalisa [80]
Yes, it is the correct answer.
8 0
3 years ago
When asked to write the domain for the equation y= |x - 6| + 3, Mary wrote the Domain is y < 3. What mistake(s) did Mary make
castortr0y [4]

Answer:

Ok, the domain is the set of values that we can input in a function.

In this case, we have:

y = Ix - 6I + 3.

Notice that there is no restriction here, x can actually take any value, then the domain will be the set of all real numbers.

The correct domain is x, x ∈ R

Now, if we had (for example) something like:

y = Ix - 6I < 3

Now we have a restriction in the domain because we can not have y equal or larger than 3.

To find the domain, we can break the absolute value:

Ix - 6I < 3

is equivalent to:

-3 < x - 6 < 3

now let's add 6 in each side.

-3 + 6 < x - 6 + 6 < 3 + 6

3 < x < 9

That will be the domain in that case.

6 0
3 years ago
What is m∠Q ?
ddd [48]
Unlike the previous problem, this one requires application of the Law of Cosines.  You want to find angle Q when you know the lengths of all 3 sides of the triangle.

Law of Cosines:  a^2 = b^2 + c^2 - 2bc cos A

Applying that here:

                           40^2 = 32^2 + 64^2 - 2(32)(64)cos Q

Do the math.  Solve for cos Q, and then find Q in degrees and Q in radians.

7 0
3 years ago
Read 2 more answers
Suppose that in an alternate universe, the gambler's fallacy is true: the more a gambler loses, the more likely she is to win th
stepladder [879]

Answer and explanation:

The gambler's fallacy is the fallacy of belief that if an event such as a loss occurs more frequently in the past, it is less likely to happen in the future. We assume here that this belief is true, therefore

If she loses, her probability of winning increases =3/4

If she wins, her probability to win is normal =1/2

Given that probability of winning is 1/2

Probability of losing is 1-1/2=1/2

Probability that she wins the tournament is probability that she wins the first two games and loses the last or wins the first game, loses the second and wins the last or loses the first game and wins the last two games or probability that she wins all three games

=1/2*1/2*1/2+1/2*1/2*3/4+1/2*3/4*1/2+1/2*1/2*1/2

=25/48

Probability of winning the tournament if she loses the first game

=1/2*3/4*1/2= 3/16

Note: whenever there is "or" in probability, you add

4 0
3 years ago
the expression 12g gives the number of kilometers a car can travel using g liters of gasoline how far can this car travel on 5 1
dmitriy555 [2]
The answer is 66 kilometers.

Start with the given expression: 12g where 'g' standts for the liters of gasoline.

Input your data and solve: 12 * 5.5 = 66
3 0
3 years ago
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