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2 years ago

Find an equation of the line parallel to y=2x+3 and that passes through the point (5,3)

Mathematics

2 answers:

timama [110]2 years ago

5 0

Answer:

y = 2x - 7

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = 2x + 3 ← is in slope- intercept form

with slope m = 2

Parallel lines have equal slopes , then

y = 2x + c ← is the partial equation

To find c substitute (5, 3 ) into the partial equation

3 = 10 + c ⇒ c = 3 - 10 = - 7

y = 2x - 7 ← equation of parallel line

Ronch [10]2 years ago

3 0

Answer:

Step-by-step explanation:

First line: y = 2x + 3 , m = 2

Second line: m = 2 and pass ( 5 , 3 )

y - 3 = 2( x - 5 ) ⇔ <em>y = 2x - 7</em>

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Umnica [9.8K]

Answer:

N$ 612.5

Step by step explaination:

Given,

Principal or'P'=N$2500

Time or'n'=3 years & 6 months or 3.5 years

Rate of profit or 'r'=7% or 7/100

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3 years ago

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3 years ago

Read 2 more answers

Write the expression for the Area of the polygon BORT MO 6 A= O A = 6m + mp O A = mp + 1/2(6m) O A = mp + 6p

anyanavicka [17]

We are asked to determine the area of the given figure. To do that we will divide the figure into a square and a triangle. The area of the square is the product of its dimension, therefore, the area is:

$A_{sq}=mp$

The area of the triangle is given by the following formula:

$A_t=\frac{bh}{2}$

Where "b" is the base and "h" is its height. Replacing the values:

$A_t=\frac{(6)(m)}{2}=\frac{1}{2}6m$

The total area is the sum of both areas:

$A=A_{sq}+A_t$

replacing the areas:

$A=mp+\frac{1}{2}6m$

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1 year ago

Y=0.5x+3.5 on graphs

tresset_1 [31]

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3 years ago