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4 years ago

Explain why the equation 2L + 2W = 4(L - W + 7) is true for the rectangle

2 answers:

7 0

you can find the perimeter of rectangle if you subtract the width from the length, add 7 inches, and multiply the result by 4. b.Explain the equation 2L +2w=4(L-w+7)

nikklg [1K]4 years ago

6 0

P = 2W +2L step is keep 2L in one side of equation , and move every thing else to the other side. In moving any quantity from one side to other, change the sign. ( equivalent of adding or subtracting equal quantity from both sides of equation). 2L = P - 2W divide both sides by 2: L = p/2 - w Step is the same as solving X in equation of 8 = 2X + 16 2X = 8 -16 = 8 X =4 . But, here you solve one variable in terms of other variables. 9/9/2013 | Parviz F.

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Can anyone tell me how you could describe this answer to the equation?

DanielleElmas [232]

The end behavior of the given polynomial is that as x → -∞ or x → ∞, then, f(x) → 5

<h3>What is the end behavior of the Polynomial?</h3>

We are given the polynomial;

f(x) = 5x/(x - 25)

Now, we want to find the limits as x → ±∞. Let us rearrange the given polynomial to get; f(x) = 5/(1 - (25/x))

Thus, applying limits we have;'

lim x → ±∞ [5/(1 - (25/x))]

From algebraic limit laws we know that;

If f(x) = k, then;

lim x → +∞ [f(x)] = k

Also, lim x → -∞ [f(x)] = k

Thus, applying limits at infinity to our polynomial gives;

lim x → ±∞ [5/(1 - (25/x))] = 5/(1 - 0) = 5

This is because lim x → ∞ for 1/x is 0.

Thus, f(x) has horizontal asymptotes at y = 5

Thus, we conclude that the end behavior is that as x → -∞ or x → ∞, then, f(x) → 5

Read more about Polynomial End behavior at; brainly.com/question/20347699

#SPJ1

8 0

2 years ago

HELPPP PLEASEEE g(t) = 6 - 1 g -) = -7

DedPeter [7]

t is -1

g ( t ) = 6t-1

g (-1) = 6(-1)-1

= -6-1 = -7

6 0

3 years ago

Solve the formula for the variable h f=12gh

Contact [7]

To solve for variable h flip the equation. You get: 12gh=f. After, divide both sides by 12 to get your answer: h=f/12g

8 0

3 years ago

Farmer Company purchased equipment on January 1, Year 1 for $82,000. The equipment is estimated to have a 5-year life and a salv

aalyn [17]

Answer:

option (a) $6,240

Step-by-step explanation:

Given:

Purchasing cost of the equipment = $82,000

Estimated life = 5 years

Salvage value = $4,000

Revised expected life = 8 years

Now,

Depreciation per year = $\frac{\textup{82,000-4,000}}{\textup{5}}$

therefore,

The accumulated Depreciation at the beginning of year 4

= Annual depreciation × years passed

= 15,600 × 3

= $46,800

Thus,

The book value at the beginning of year 4

= Purchasing cost - Depreciation

= $82,000 - $46,800

= $35,200

Now,

The remaining life = Revised estimated life - Years passed

= 8 - 3

= 5 years

therefore,

Depreciation expense = $\frac{\textup{book value at the beginning of year 4 - salvage value}}{\textup{Revised estimated life}}$

= $\frac{\textup{35,200 - 4000}}{\textup{5}}$

= $6,240

Hence,

The correct answer is option (a) $6,240

7 0

3 years ago

Given A. 88 B. 64 C. 92 D. 52

victus00 [196]

Maybe 88 not sure that is the givin

5 0

3 years ago