if you know the distance around a rectangle could you find the area of the rectangle? OPEN ENDED QUESTION HELP

Mathematics

1 answer:

Fudgin [204]3 years ago

3 0

Answer:

yes

Step-by-step explanation:

yeah you put all the distances together and then you get the area.

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Greeley [361]

Answer:

Step-by-step explanation:

81/9 is 9, so in one pack there would be 9

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3 years ago

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Find the nth term of this quadratic sequence 3, 8, 15, 24, 35, ...

SpyIntel [72]

Answer:

$s_n = (n+1)^2-1$

Step-by-step explanation:

This assumes that the first item coincides with n=1.

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3 years ago

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4 years ago

8/x-5 - 9/x-4 = 5/x^2-9x+20

adelina 88 [10]

If you're using the app, try seeing this answer through your browser: brainly.com/question/2752942

_______________

Solve the equation:

$\mathsf{\dfrac{8}{x-5}-\dfrac{9}{x-4}=\dfrac{5}{x^2-9x+20}\qquad\qquad(x\ne 5~and~x\ne 4)}$

Reduce the fractions at the left side so that they have the same denominator:

$\mathsf{\dfrac{8(x-4)}{(x-5)(x-4)}-\dfrac{9(x-5)}{(x-4)(x-5)}=\dfrac{5}{x^2-9x+20}}\\\\\\
\mathsf{\dfrac{8x-32}{x^2-4x-5x+20}-\dfrac{9x-45}{x^2-4x-5x+20}=\dfrac{5}{x^2-9x+20}}\\\\\\
\mathsf{\dfrac{8x-32}{x^2-9x+20}-\dfrac{9x-45}{x^2-9x+20}=\dfrac{5}{x^2-9x+20}}\\\\\\
\mathsf{\dfrac{8x-32-(9x-45)}{x^2-9x+20}=\dfrac{5}{x^2-9x+20}}$

Numerators must be equal:

$\mathsf{8x-32-(9x-45)=5}\\\\
\mathsf{8x-32-9x+45=5}\\\\
\mathsf{8x-9x=5+32-45}\\\\
\mathsf{-x=-8}\\\\
\mathsf{x=8}\quad\longleftarrow\quad\textsf{this is the solution.}$

I hope this helps. =)

Tags: rational equation fraction solution algebra

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3 years ago

The annual expenditure of the US federal government is approximately 4 44 trillion dollars. If a one dollar bill is 0 . 0 0 0 1

kaheart [24]

Answer:

A stack of 4 trillion one dollar bills will be $4\times 10^8$ meters.