Step-by-step explanation:
<h3>Part A</h3>
<u>Angle measures:</u>
- a = x = z = 51° (as vertical angles and corresponding angles)
- b = d = y = w = 180° - 51° = 129° (as supplementary angles and corresponding angles)
<h3>Part B</h3>
Supplementary angles for a linear pair and sum to 180°.
<u>Examples are:</u>
- a and b or
- a and d or
- x and y etc.
What is the situation from the problem
Answer:
2000 = 600 + 2/5x ; 3500 ft
How To Solve:
2000 = 600 + 2/5x
Combine multiplied terms into a single fraction
2000 = 600 + 2/5x
2000 = 600 + 2x/5
Subtract 600 from both sides of the equation
2000 = 600 + 2x/5
2000 - 600 = 600 + 2x/5 - 600
Simplify
Subtract the numbers
1400 = 600 + 2x/5 − 600
Subtract the numbers
1400 = 2x/5
Solution
X = 3500
Answer:
The population of bacteria can be expressed as a function of number of days.
Population = ![\[5*2^{n-1}\]](https://tex.z-dn.net/?f=%5C%5B5%2A2%5E%7Bn-1%7D%5C%5D)
where n is the number of days since the beginning.
Step-by-step explanation:
Number of bacteria on the first day=![\[5 * 2^{0} = 5\]](https://tex.z-dn.net/?f=%5C%5B5%20%2A%202%5E%7B0%7D%20%3D%205%5C%5D)
Number of bacteria on the second day = ![\[5 * 2^{1} = 10\]](https://tex.z-dn.net/?f=%5C%5B5%20%2A%202%5E%7B1%7D%20%3D%2010%5C%5D)
Number of bacteria on the third day = ![\[5*2^{2} = 20\]](https://tex.z-dn.net/?f=%5C%5B5%2A2%5E%7B2%7D%20%3D%2020%5C%5D)
Number of bacteria on the fourth day = ![\[5*2^{3} = 40\]](https://tex.z-dn.net/?f=%5C%5B5%2A2%5E%7B3%7D%20%3D%2040%5C%5D)
As we can see , the number of bacteria on any given day is a function of the number of days n.
This expression can be expressed generally as where n is the number of days since the beginning.
Y=4x-5... if you were asking for that in words
