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yawa3891 [41]
3 years ago
7

A sprinkler that sprays water in a circular area can be adjusted to spray up to 30 feet. Turning the radius-reduction screw on t

he top of the nozzle let's people reduce the radius by up to 25percent. To the nearest tenth, what is the maximum area of lawn that can be watered by the sprinkler if the radius reduction is used at full capacity?
Mathematics
2 answers:
topjm [15]3 years ago
8 0

Answer:

1,590.4 sq ft

Step-by-step explanation:

zheka24 [161]3 years ago
5 0

Answer:

Area_lawn = 393.75 π ft^2

Step-by-step explanation:

Maximum radius : 30 feet

Minimum radius:  30 feet - 0.25*(30feet)  =  22.5 feet

(25 percent reduction)

To find the area of lawn that can be watered, we just need to calculate the area for the maximum radius and the minimum radius, and then subtract them.

Since the sprinklers have a circular area:

Area = π*radius^2

Max area  = π*(30 ft)^2 = 900π ft^2

Min area  = π*(22.5 ft)^2 = 506.25π ft^2

Maximum area of lawn that can be watered by the sprinkler:

Area_lawn = Max area - Min area = 900π ft^2 -506.25π ft^2

Area_lawn = 393.75 π ft^2

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Answer:

a) 99.97%

b) 65%

Step-by-step explanation:

• 68% of data falls within 1 standard deviation from the mean - that means between μ - σ and μ + σ.

• 95% of data falls within 2 standard deviations from the mean - between μ – 2σ and μ + 2σ.

• 99.7% of data falls within 3 standard deviations from the mean - between μ - 3σ and μ + 3σ.

Mean of 98.35°F and a standard deviation of 0.64°F.

a. What is the approximate percentage of healthy adults with body temperatures within 3 standard deviations of the mean, or between 96.43°F and 100.27°F?

μ - 3σ

98.35 - 3(0.64)

= 96.43°F

μ + 3σ.

98.35 + 3(0.64)

= 100.27°F

The approximate percentage of healthy adults with body temperatures is 99.97%

b. What is the approximate percentage of healthy adults with body temperatures between 97 .71°F and 98.99°F?

within 1 standard deviation from the mean - that means between μ - σ and μ + σ.

μ - σ

98.35 - (0.64)

= 97.71°F

μ + σ.

98.35 + (0.64)

= 98.99°F

Therefore, the approximate percentage of healthy adults with body temperatures between 97.71°F and 98.99°F is 65%

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Answer:

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Step-by-step explanation:


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