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madam [21]
3 years ago
14

Evaluate sec960°. 1. -2 2. - 2 sqrt3/3 3. 2sqrt 3/3 4. 2

Mathematics
2 answers:
Eduardwww [97]3 years ago
7 0

Answer:

-2

Step-by-step explanation:

We want to evaluate;

\sec960\degree

We use the reciprocals of trigonometric ratios to obtain;

\sec960\degree=\frac{1}{\cos960\degree}

The 960 degree angle makes an angle of 60 degree with the positive direction of the x-axis and it is in the 3rd quadrant.

This implies that;

\sec960\degree=\frac{1}{-\cos60\degree}

We use special trigonometric ratios to obtain;

\sec960\degree=\frac{1}{-\frac{1}{2}}

\sec960\degree=-2

mash [69]3 years ago
3 0

Answer:

Option 1. ( -2)

Step-by-step explanation:

sec (960°)

= sec [ 360 × 2 + 180 + 60° ]

This signifies when we draw 960° it revolves 360° twice 180° once then 60° in third quadrant in positive direction.

That means sec 960 = -(sec60)

                                   = -(\frac{1}{cos60})

                                   = \frac{-1}{\frac{1}{2} }

                                   = (-2)

Option 1. ( -2) is the answer.

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spin [16.1K]

Answer:

m<3 = 66°

Step-by-step explanation:

<3 is an angle with its vertex inside the circle shown in the diagram. This, it's an internal angle.

The measure of an internal angle is equal to half the sum of the measure of the arcs intercepted.

Thus, the equation that shows relationship between <3 and arc WX and arc YZ is shown below:

m<3 = ½(40 + 92)

m<3 = ½(132)

m<3 = 66°

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3 years ago
C is the point (-301, 601)<br> Does C lie on the straight line passing through A and B?
Marat540 [252]

Answer:

There is no picture or graph to go with the question so I am afraid I will not be able to give you a specific answer.

To find out if a point (x, y) is on the graph of a line, we plug in the values into that equation and see if we get a true statement, such as 10 = 10. If we get something different, like 6 = 4, we know that the point is not on the line because it does not satisfy the equation. Plug in (-301, 601) into the equation of the line to see whether that point lies on it or not.

Step-by-step explanation:

Suppose the equation of the straight line that passes through E and F is this:

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We are to figure out whether or not the point (1, 10) lies on that line. In order to do this we would plug in (1, 10) into the equation, with 1 being x and 10 being y.

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If you were to provide an image or graph that shows the equation of line AB then perhaps I would be able to answer your question with a specific answer.

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