Cual es la raíz cuadrada de 481

A print company will print business cards for $.10 each plus a setup charge of $12. Another print company offers business cards

bonufazy [111]

Let the number of cards equal x.

Set up an equation for both companies, set equal to each other and solve for x.

0.10x + 12 = 0.12x + 10

Subtractb0.10x from both sides:

12 = 0.02x + 10

Subtract 10 from both sides:

2 = 0.02x

Divide both sides by 0.02:

X = 2/0.02

X = 100

100 cards would be the same price for both companies.

3 0

3 years ago

Simplify the expression so there is only one positive power for each base. (5^-2 x 4^-4)^-2

faltersainse [42]

$(a\cdot b)^n=a^n\cdot b^n\\(a^n)^m=a^{n\cdot m}\\\\(5^{-2}\cdot4^{-4})^{-2}=(5^{-2})^{-2}\cdot(4^{-4})^{-2}=5^{-2\cdot(-2)}\cdot4^{-4\cdot(-2)}\\\\=\boxed{5^4\cdot4^8}\to\fbox{A.}$

6 0

3 years ago

Read 2 more answers

The true average diameter of ball bearings of a certain type is supposed to be 0.5 in. A one-sample t test will be carried out t

yulyashka [42]

Complete Question

The complete question is shown on the first uploaded image

Answer:

a

C

b

C

c

C

d

A

Step-by-step explanation:

From the question we are told that

The population mean is $\mu = 0.5 \ in$

Generally the Null hypothesis is $H_o : \mu = 0. 5 \ in$

The Alternative hypothesis is $H_a : \mu \ne 0.5 \ in$

Considering the parameter given for part a

The sample size is n = 15

The test statistics is t = 1.66

The level of significance $\alpha = 0.05$

The degree of freedom is evaluated as

$df = n- 1$

$df = 15- 1$

$df = 14$

Using the critical value calculator at (social science statistics web site )

$t_{\frac{\alpha}{2} ,df } = t_{\frac{0.05 }{2} ,14} = 2.145$

We are making use of this $t_{\frac{\alpha }{2} }$ because it is a one-tail test

Looking at the value of t and $t_{\frac{\alpha }{2} }$ the we see that $t < t_{\frac{\alpha }{2} }$ so the null hypothesis would not be rejected

Considering the parameter given for part b

The sample size is n = 15

The test statistics is t = -1.66

The level of significance $\alpha = 0.05$

The degree of freedom is evaluated as

$df = n- 1$

$df = 15- 1$

$df = 14$

Using the critical value calculator at (social science statistics web site )

$t_{\frac{\alpha}{2} ,df } = t_{\frac{0.05 }{2} ,14} = -2.145$

Looking at the value of t and $t_{\frac{\alpha}{2} ,df }$ the we see that t does not lie in the area covered by $t_{\frac{\alpha}{2} , df }$ (i.e the area from -2.145 downwards on the normal distribution curve ) hence we fail to reject the null hypothesis

Considering the parameter given for part c

The sample size is n = 26

The test statistics is t = -2.55

The level of significance $\alpha = 0.01$

The degree of freedom is evaluated as

$df = n- 1$

$df = 26- 1$

$df = 25$

Using the critical value calculator at (social science statistics web site )

$t_{\frac{\alpha}{2} ,df } = t_{\frac{0.01 }{2} ,25} = 2.787$

Looking at the value of t and $t_{\frac{\alpha }{2} }$ the we see that t does not lie in the area covered by $t_{\alpha , df }$ (i.e the area from -2.787 downwards on the normal distribution curve ) hence we fail to reject the null hypothesis

Considering the parameter given for part d

The sample size is n = 26

The test statistics is t = -3.95

The level of significance $\alpha = 0.01$

The degree of freedom is evaluated as

$df = n- 1$

$df = 26- 1$

$df = 25$

Using the critical value calculator at (social science statistics web site )

$t_{\frac{\alpha}{2} ,df } = t_{\frac{0.01 }{2} ,25} = -2.787$

Looking at the value of t and $t_{\frac{\alpha}{2} }$ the we see that t lies in the area covered by $t_{\alpha , df }$ (i.e the area from -2.787 downwards on the normal distribution curve ) hence we reject the null hypothesis

6 0

3 years ago

Suppose that x and y are positive integers such that x^2 * y^3=46656. What is the sum of all possible values of x?

Nostrana [21]

Answer:

252

Step-by-step explanation:

x² * y³=46656

Prime factors of 46656:

46656 = 2⁶3⁶

Possible values of x:

(2*3)³= 216
3³ = 27
2³ = 8
1

Sum of them:

216 + 27 + 8 + 1 = 252

3 0

3 years ago

Help please!!!!!!!!!!!!!

n200080 [17]

Answer:

A. Nothing, Paul is correct

Step-by-step explanation:

Tangent to a circle is a line that touches the circle at one point. At the point of contact, tangent to a circle is always perpendicular to the radius.
If two tangents are drawn from a common external point to a circle, then the two tangents have equal tangent segments.
Tangent segment means line joining to the external point and the point of contact to the circle.

7 0

4 years ago