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kakasveta [241]

2 years ago

8

if you solve this with the steps your littearly such a pro pro pro pro pro pro pro pro pro pro prohacker

2 answers:

Yuri [45]2 years ago

8 0

Answer:

maybe 1.5 songs per minute

Sever21 [200]2 years ago

7 0

1.5 songs per min

Divide the denominator with the numerator in a way that the denominator becomes 1

30 divided by 20 is 1.5

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Question 5 (1 point)

riadik2000 [5.3K]

Answer:

The area of sector AOB is 75.36 unit²

Step-by-step explanation:

Consider the provided information.

Circle O with minor arc AB=60 degrees and OA =12.

We need to find the area of sector.

Area of the sector: $A=\frac{\theta }{360} \times \pi r^2$

Substitute $\theta=60$ and r =12 in above formula.

$A=\frac{60}{360} \times 3.14\times (12)^2$

$=\frac{1}{6} \times 3.14\times 144$

$=24\times 3.14$

$=75.36$

Hence, the area of sector AOB is 75.36 unit²

8 0

3 years ago

Which one of these is x please help

sesenic [268]

Answer:

1/2

Step-by-step explanation:

7 0

3 years ago

(5x^2+3x+4)-(2x^2+5x-1)

DedPeter [7]

Answer:
The answer is (3x^2-2x+5)

6 0

3 years ago

7 to the negative 3rd porwer times 7 to the negative 2nd porwer times 2 the 0 power divided by 7 to negative 1st power times 7 t

Jobisdone [24]

oof

remember some rules

(a/b)(c/d)=(ac)/(bd)

$\frac{x^a}{x^b}=x^{a-b}$

$x^0=1$

$(x^a)(x^b)=x^{a+b}$

$x^{-a}=\frac{1}{x^a}$

$\frac{(7^{-3})(7^{-2})(2^0)}{(7^{-1})(7^{-4})(2^3)}=$

$\frac{(7^{-3-2})(2^0)}{(7^{-1-4})(2^3)}=$

$\frac{(7^{-5})(2^0)}{(7^{-5})(2^3)}=$

$(\frac{7^{-5}}{7^{-5}})(\frac{2^0}{2^3})=$

$(7^{-5-(-5)})(2^{0-3})=$

$(7^0)(2^{-3})=$

$\frac{1}{2^3}=$

$\frac{1}{8}$

7 0

3 years ago

Solve what is 1/2 x 15

Andreas93 [3]

Answer:

7.5

Step-by-step explanation:

it's basically just 15 divided by 2

8 0

3 years ago